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3 years ago

The acceleration of the object at time t = 0.7 s is most nearly equal to which of the following?

1 answer:

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We have that for the Question "the acceleration of the object at time t = 0.7 s is most nearly equal to which of the following?"

it can be said that the acceleration of the object at time t = 0.7 s is most nearly equal to the slope of the line connecting the origin and the point where the graph where the graph crosses the 0.7s grid line

From the question we are told

the acceleration of the object at time t = 0.7 s is most nearly equal to which of the following?

Generally the equation for the Force is mathematically given as

F=\frac{F}{dx}

Therefore

F=-kdx

k=600Nm^{-1}

now

K.E=0.5x ds^2

K.E=600*(-0.1^2)

K.E=3J

Therefore

the acceleration of the object at time t = 0.7 s is most nearly equal to the slope of the line connecting the origin and the point where the graph where the graph crosses the 0.7s grid line

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The magnetic field due to a straight wire carrying current is given by

B = μo• I / 2πr

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r Is the distance of point from the wire.

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B = μo•I / 2πR

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A 20 kg box is being pulled across a floor by a horizontal rope. The tension in the rope is 99 Newtons. The coefficient of frict

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Susie (45kg) and Troy (65 kg) are sitting 2 meters apart. They smile at each other. What is the gravitational force between them

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The gravitational force between Susie and Troy is d) $4.9 \cdot 10^{-8}N$

Explanation:

The magnitude of the gravitational force between two objects is given by

$F=G\frac{m_1 m_2}{r^2}$

where :

$G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}$ is the gravitational constant

m1, m2 are the masses of the two objects

r is the distance between them

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$m_1 = 45 kg$ is Susie mass

$m_2 = 65 kg$ is Troy mass

r = 2 m is the distance between them

Substituting into the equation, we find the gravitational force between Susie and Troy:

$F=(6.67\cdot 10^{-11})\frac{(45)(65)}{(2)^2}=4.9\cdot 10^{-8}N$

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3 years ago

If you lose control of your vehicle and collide with a fixed object, such as a tree, at 60 m.p.h., the force of impact is the sa

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You can compare the velocity of the car, 60 mph, with the velocity that a mass would acquire when falls from certain height.

First, convert 60 mph to m/s:

60 miles/h * 1.60 km/mile * 1000 m/km * 1h/3600s = 26.67 m/s

Second, calculate from what height a body in free fall reachs 26.67 m/s velocity when hits the floor.

free fall => Vf^2 = 2g*H => H = Vf^2 / (2g)

H = (26.67m/s)^2 / (2*9.8 m/s) = 36.2 m

If you consider that the height between the floors of a building is approximately 3.6 m, you get 36.2 m / 3.6 m/floor = 10 floors.

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