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sergejj [24]
3 years ago
6

A car is driving on the road. The car starts to decelerate at -3 m/s2. It stops moving after 125

Physics
1 answer:
galina1969 [7]3 years ago
8 0

Answer:

27.39 m/s

Explanation:

From the question given above, the following data were obtained:

Deceleration (a) = –3 m/s²

Distance (s) = 125 m

Final velocity (v) = 0 m/s

Initial velocity (u) =?

The initial velocity (u) of the car can be obtained as follow:

v² = u² + 2as

0² = u² + (2 × –3 × 125)

0 = u² + (– 750)

0 = u² – 750

Collect like terms

0 + 750 = u²

750 = u²

Take the square root of both side

u = √750

u = 27.39 m/s

Thus, the initial velocity of the car was 27.39 m/s

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Answer:

0.0059

Explanation:

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Here,

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8 0
3 years ago
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Answer:

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= 9b + 5

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5 0
3 years ago
008 (part 1 of 3) 10.0 points A 3.2 kg object is subjected to two forces, F~ 1 = (1.9 N) ˆı + (−1.9 N) ˆ and F~ 2 = (3.8 N) ˆı
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Answer:

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3 years ago
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Shtirlitz [24]

Answer:

3272.4 Hz

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