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xz_007 [3.2K]
3 years ago
8

When a rope is wrapped around a wheel (or pulley) and pulled, the lever arm is the ________ Blank 1 of the wheel and the angle b

etween this and the force is ALWAYS ________ degrees. Blank 2
Physics
1 answer:
m_a_m_a [10]3 years ago
3 0

Answer:

the DISTANCE between the lever arm and the force is always 90º

Explanation:

In this exercise, you are asked to complete the missing words so that the phrase makes sense.

note that the torque is

              τ = F x r

where bold indicates vectors

When the rope is pulled, the DISTANCE between the lever arm and the force is always 90º

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Shari uses the data in the table to predict how her weight on Venus would compare with her weight on Earth.
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Answer :  <em>Her weight is lower on Venus because the acceleration due to gravity is lower.</em>

Explanation :

Venus is also called as Earth's twin. This is because both the mass and the size of Earth and Venus are almost same. The acceleration due to gravity on earth is 9.8\ m/s^2 while on Venus is 8.87\ m/s^2.

So, when Shari measure her weight on Venus she found her weight is lower on Venus. This is because the acceleration due to gravity is lower on the surface of Venus as compared to the Earth.

Since,    w=mg

i.e. weight depends on g.

<em>So, correct prediction is (b)</em>

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3 years ago
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Which describes Einstein’s idea of space and time?
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Suppose the electric field in problems 2 was caused by a point charge. The test charge is moved to a distance twice as far from
mojhsa [17]

Answer:

it is reduced four times.

Explanation:

By definition, the electric field is the force per unit charge created by a charge distribution.

If the charge creating the field is a point charge, the force exerted by it on a test charge, must obey Coulomb´s Law, so, it must be inversely proportional to the square of the distance between the charges.

So, if the distance increases twice, as the force is inversely proportional to the square of the distance, and the square of 2 is 4, this means that the magnitude of the force exerted on the test charge must be 4 times smaller.

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3 years ago
A block of mass 0.221 kg is placed on top of a light, vertical spring of force constant 5365 N/m and pushed downward so that the
Anvisha [2.4K]

Answer:

The maximum height above the point of release is 11.653 m.

Explanation:

Given that,

Mass of block = 0.221 kg

Spring constant k = 5365 N/m

Distance x = 0.097 m

We need to calculate the height

Using stored energy in spring

U=\dfrac{1}{2}kx^2...(I)

Using gravitational potential energy

U' =mgh....(II)

Using energy of conservation

E_{i}=E_{f}

U_{i}+U'_{i}=U_{f}+U'_{f}

\dfrac{1}{2}kx^2+0=0+mgh

h=\dfrac{kx^2}{2mg}

Where, k = spring constant

m = mass of the block

x = distance

g = acceleration due to gravity

Put the value in the equation

h=\dfrac{5365\times(0.097)^2}{2\times0.221\times9.8}

h=11.653\ m

Hence, The maximum height above the point of release is 11.653 m.

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