What are you solving for???
Answer:
We conclude that the 76% is of the learning in this process.
Step-by-step explanation:
We know that the company Z is just starting to make a brand new product it has never made before. It has completed two units so far. The first unit took 29 hours to complete and the next unit took 22 hours. We calculate the estimate of the learning percentage in this process:
22/29 = 0.76 = 76%
We conclude that the 76% is of the learning in this process.
Okay so 300 meters per minute and he ran 8 minutes..
300x8=2400
He still had 600 left to go...
2400+600=3,000
He had to run three times longer than Eric...
3000/3=1000
Does that make sense?
The length of segment F'G' is 7 units
<h3>Length</h3>
The length of a line segment is the number of units on the line.
<h3>
Coordinates </h3>
The coordinates are given as:
![F = (-2,-4)](https://tex.z-dn.net/?f=F%20%3D%20%28-2%2C-4%29)
![G = (5,-4)](https://tex.z-dn.net/?f=G%20%3D%20%285%2C-4%29)
<h3>
Distance </h3>
Start by calculating the length of segment FG using the following distance formula
![FG = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}](https://tex.z-dn.net/?f=FG%20%3D%20%5Csqrt%7B%28x_1%20-%20x_2%29%5E2%20%2B%20%28y_1%20-%20y_2%29%5E2%7D)
So, we have:
![FG = \sqrt{(-2- 5)^2 + (-4+ 4)^2}](https://tex.z-dn.net/?f=FG%20%3D%20%5Csqrt%7B%28-2-%205%29%5E2%20%2B%20%28-4%2B%204%29%5E2%7D)
![FG = \sqrt{49}](https://tex.z-dn.net/?f=FG%20%3D%20%5Csqrt%7B49%7D)
![FG = 7](https://tex.z-dn.net/?f=FG%20%3D%207)
The transformation of segment FG to F'G' is a rigid transformation.
This means that:
The lengths of segments FG and F'G' are the same
So, we have:
![F'G' = 7](https://tex.z-dn.net/?f=F%27G%27%20%3D%207)
Hence, the length of segment F'G' is 7 units
Read more about length at:
brainly.com/question/17206319
Answer:
If
x
y
=
sin
x
, using the product rule:
y
+
x
y
'
=
cos
x
□
y
'
+
y
'
+
x
y
'
'
=
−
sin
x
△
△
x
+
□
⇒
2
y
'
x
+
y
'
'
+
y
+
x
y
'
=
−
sin
x
x
+
cos
x
As
y
=
sin
x
x
and
y
+
x
y
'
=
cos
x
:
2
y
'
x
+
y
'
'
+
cos
x
=
−
y
+
cos
x
⇒y''+2y,
x+y=0