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grandymaker [24]
3 years ago
13

A hotel elevator ascends 200m with maximum speed of 5m/s. Its acceleration and deceleration both have a magnitude of 1.0m/s2. Pa

rt APart complete How far does the elevator move while accelerating to full speed from rest? Express your answer with the appropriate units. 12.5 m Previous Answers Correct Part B How long does it take to make the complete trip from bottom to top? Express your answer with the appropriate units.
Physics
1 answer:
ValentinkaMS [17]3 years ago
4 0

Answer:

45 s .

Explanation:

The accelerator will first accelerate , then move with uniform velocity and at last it will decelerate to rest .

displacement s = ?

acceleration a = 1 m /s²

Final speed v = 5 m/s

initial speed u = 0

v² = u² + 2as

5² = 0 + 2 x 1 x s

s = 12.5  m

B)  Let time of acceleration or deceleration be t

v = u + a t

5 = 0 + 1 t

t = 5 s

Similarly displacement during deceleration = 12.5 m

Total distance during uniform motion = 200 - ( 12.5 + 12.5 ) =  175 m .

velocity of uniform motion = 5 m /s

time during which there was uniform velocity = 175 / 5 = 35 s

Total time = 5 + 35 + 5 = 45 s .

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Formula:
s2008m [1.1K]

Answer:

55N

Explanation:

Using Newton's second law of motion:

F=ma

Force=mass × acceleration

F=25×2.2

F=55N

So 55 Newtons are needed

8 0
3 years ago
Suppose a ray of light traveling in a material with an index of refraction n a reaches an interface with a material having an in
KATRIN_1 [288]

Answer: C and D

Explanation: One of the first rule for total internal reflection to occur is that the ray must move from a dense to a less dense medium, hence refractive index of medium a must be greater than that of b.

When a ray moves from a dense to a less dense medium, the refracted ray moves away from the normal thus increasing the size of the angle of refraction (total internal refraction occurs when the angle of refraction is 90° and the angle of incidence at this point is known as the critical angle), hence the angle of incidence must be greater than the critical angle.

These points verifies option C and D

5 0
3 years ago
A hotel elevator ascends 200m with maximum speed of 5m/s. Its acceleration and deceleration both have a magnitude of 1.0m/s2. Pa
ValentinkaMS [17]

Answer:

45 s .

Explanation:

The accelerator will first accelerate , then move with uniform velocity and at last it will decelerate to rest .

displacement s = ?

acceleration a = 1 m /s²

Final speed v = 5 m/s

initial speed u = 0

v² = u² + 2as

5² = 0 + 2 x 1 x s

s = 12.5  m

B)  Let time of acceleration or deceleration be t

v = u + a t

5 = 0 + 1 t

t = 5 s

Similarly displacement during deceleration = 12.5 m

Total distance during uniform motion = 200 - ( 12.5 + 12.5 ) =  175 m .

velocity of uniform motion = 5 m /s

time during which there was uniform velocity = 175 / 5 = 35 s

Total time = 5 + 35 + 5 = 45 s .

4 0
3 years ago
What the kinetic Energy of 80kg<br> object this is Moving with a Speed<br> of 23 m/s
Katyanochek1 [597]

Explanation:

Kinetic Energy Formula = ½mv²

  • ½×800kg×(23m/s)²
  • 400kg×529m²/s²
  • 211600 kg•m²/s²
  • 211700 joule Answer

4 0
2 years ago
A bullet with a mass of 0.3 kg is fired out of a gun with a mass of 4 kg at 600 m/s. What is the recoil velocity on the gun?
slavikrds [6]

Answer:

According to the Conservation of Momentum,

Momentum of the gun = momentum of the bullet

M(gun)×V(gun)=m(bullet)×v(bullet)

4kg × V = 0.3kg × 600m/s²

V = (0.3 × 600)/4 = 45 m/s

The recoil velocity on the gun is <em><u>45 m/s</u></em>

<h3><u>45 m/s</u> is the right answer.</h3>
4 0
3 years ago
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