Question

What is the minimum total energy released when

Answer 1

Answer:

(1) $1.64 \times 10^{-13} J$

Explanation:

Energy released in this process is given by

$Q = \Delta m c^2$

here we have

$\Delta m = 9.1 \times 10^{-31} kg$

since here mass of two electrons converted into energy so we have

$Q = 2(9.1 /times 10^{-31})(3\times 10^8)^2$

$Q = 1.64 \times 10^{-13} J$

so here energy released is the energy of rest mass energy due to two charges i.e. electrons and positrons

Answer 2

What is the minimum total energy released when an electron and its antiparticle (positron) annihilate each other?
The minimum total energy released when an electron and its antiparticle (positron) annihilate each other is 2.73 × 10^–22 J. The answer is number 4.