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mestny [16]
3 years ago
10

Which theorem proves that the triangles are congruent? A. AAS B. ASA C. SAS D. SSS

Mathematics
1 answer:
Delicious77 [7]3 years ago
5 0

Answer:

A: AAS

Step-by-step explanation:

Hopefully this helps!

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Which ordered pair is a solution of this
Stells [14]

Answer:

(-1,-2)

Step-by-step explanation:

I graphed the equation on the graph below so you can see that (-1,-2) is a solution.

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In each bouquet of flowers, there are 5 roses and 8 white carnations. Complete the table to find how many roses and carnations t
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If a manufacturer conducted a survey among randomly selected target market households and wanted to be 95​% confident that the d
katen-ka-za [31]

Answer:

We need a sample size of least 119

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Sample size needed

At least n, in which n is found when M = 0.09

We don't know the proportion, so we use \pi = 0.5, which is when we would need the largest sample size.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.09 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.09\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.09}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.09})^{2}

n = 118.6

Rounding up

We need a sample size of least 119

6 0
4 years ago
1 gallon = 4 quarts
harkovskaia [24]

Answer:

512 ounces

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find the range of each function for the domain {-4, -2, 0, 1.5, 4}. f(x) = 5x^2 + 4
andrew11 [14]
Substitute x with the members of the domain.
f(x) = 5x² + 4

Substitute with the domain of -4
f(x) = 5x² + 4
f(-4) = 5(-4)² + 4
f(-4) = 5(16) + 4
f(-4) = 80 + 4
f(-4) = 84

Substitute with the domain of -2
f(x) = 5x² + 4
f(-2) = 5(-2)² + 4
f(-2) = 5(4) + 4
f(-2) = 20 + 4
f(-2) = 24

Substitute with the domain of 0
f(x) = 5x² + 4
f(0) = 5(0)² + 4
f(0) = 5(0) + 4
f(0) = 0 + 4
f(0) = 4

Substitute with the domain of 1.5
f(x) = 5x² + 4
f(1.5) = 5(1.5)² + 4
f(1.5) = 5(2.25) + 4
f(1.5) = 11.25 + 4
f(1.5) = 15.25

Substitute with the domain of 4
f(x) = 5x² + 4
f(4) = 5(4)² + 4
f(4) = 5(16) + 4
f(4) = 80 + 4
f(4) = 84

The range of the function for those domain is {4, 24, 15.25, 84}
4 0
3 years ago
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