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katovenus [111]
3 years ago
8

The electron configuration of calcium is

Chemistry
2 answers:
-Dominant- [34]3 years ago
4 0
20 Ca :

1s², 2s², 2p⁶, 3s², 3p⁶, 4s²<span>
</span>
Answer D

hope this helps!

hammer [34]3 years ago
4 0

1s^2 2s^2 2p^6 3s^2 3p^6 4s^2.


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From the following data, calculate the average bond enthalpy for the NOH bond: NH3(g) ¡NH2(g) 1 H(g) ¢H° 5 435 kJ/mol NH2(g) ¡NH
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Answer:

The average bond enthalpy for the N-H bond is 392 kJ/mol.

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NH_3(g) \rightarrow NH_2(g) +1 H(g),\Delta H^o_{1}= 435 kJ/mol..[1]

NH_2(g) \rightarrow NH(g) + H(g),\Delta H^o_{2}= 381 kJ/mol..[2]

NH(g) \rightarrow N(g)+ 1 H(g),\Delta H^o_{3}= 360 kJ/mol..[3]

On adding [1] , [2] and [3] , we get:

NH_3(g) \rightarrow N(g) +3H(g),\Delta H^o_{4}= ?

\Delta H^o_{4}=\Delta H^o_{1}+\Delta H^o_{2}+\Delta H^o_{3}

= 435 kJ/mol+381 kJ/mol +360 kJ/mol = 1,176 kJ/mol

There three bonds N-H bond sin ammonia. Then average bond enthalpy of single N-H bond is :

\Delta H^o_{N-H}=\frac{1,176 kJ/mol}{3}=392 kJ/mol

The average bond enthalpy for the N-H bond is 392 kJ/mol.

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Why is metal a good conductor?
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How much of a 0.250 M lithium hydroxide is required to neutralize 20.0 mL of 0.345M chlorous acid?
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27.6mL of LiOH 0.250M

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6.90x10⁻³ moles ₓ (1L / 0.250mol) = 0.0276L of LiOH =

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