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IrinaK [193]
3 years ago
7

The density of a substance with a mass of 40.0g and a volume of 10ml is?

Chemistry
1 answer:
marusya05 [52]3 years ago
3 0

In this experiment you will determine the density of an unknown liquid. You will measure the mass of a known volume delivered from a pipet and use the expression:

<span><span><span>M
V</span></span><span>D=</span><span /></span>

where D = density, M = mass and V = volume to calculate the density of the unknown liquid.

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Arrange the following group of atoms in order of increasing atomic size:B,Al,Ga​
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Al,Ga,B

Explanation:

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Position (m)
Alex777 [14]

Option C. The object is returning to the start at a constant speed.

<h3>Data points of the Position vs Time graph</h3>

The following data points will be used to determine the motion of the object.

<u>Position               Time</u>

12                          4

10                          6

2                            8

0                           10

From the data above, the position of the object is decreasing towards zero or start point.

Thus, the object is returning to the start at a constant speed.

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8 0
2 years ago
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Masteriza [31]

Answer:

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If you looked at one of your body's cell under a microscope with 100x magnification, would it be larger, smaller, or the same si
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7 0
3 years ago
How much carbon would be needed to make 8.8g of carbon dioxide?<br>​
PIT_PIT [208]
The calculation for such a question can be achieved via Avogadro hypothesis

We know molar mass of CO2 is 44g/mole which is the sum of atomic masses i.e; C and 2 oxygen atoms

Molar mass of CO2 =12(C)+2*16(O) = 44 g/mole will contain 6.023 ※10^23 CO2 molecules ..

44g/mole = 6.023 ※10^23 CO2 molecules

=> 1g = (6.023/44) ※10^23 CO2 molecules

==> 8.80g = 8.80(6.023÷44)10^23 = 1.2046 ※10^23 molecules of CO2….

Thus there r 1.2046 ※10^23 molecules of CO2 in 8.80g

if u need to calculate no. of carbon atoms then multiply result by 1 and if u need no of oxygen atoms in 8.80g of co2 then multiply the result by 2 ….
7 0
2 years ago
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