Natural abundance of oxygen I think
Answer: 78.69 g of Fe
Explanation: Iron(III) oxide is Fe2O3. It has a molar mass of 159.7 g/mole. That consists of:
2 x Fe at 55.85 = 11.69 or 69.94%
3 x O at 16.0 = 48.0 or 30.06%
Therefore 112.5 grams will contain (112.5 g)*(69.94%) = 78.69 g of Fe
Answer:
Molarity = 0.202 M
7.36 g/L HCl
Explanation:
KOH + HCl ----> KCl + H2O
1 mol 1 mol
0.560mol/L *0.045L x mol/L*0.125L
0.560mol/L *0.045L = x mol/L*0.125L
x = 0.560mol/L *0.045L /0.125L= 0.2016 mol/L≈ 0.202 mol/L=0.202M HCl
M(HCl) = 1.0+35.5 = 36.5 g/mol
0.2016 mol/L*36.5 g/mol ≈ 7.36 g/L HCl