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3 years ago

Identify the step of meiosis

Physics

1 answer:

Nimfa-mama [501]3 years ago

5 0

Answer:

Since cell division occurs twice during meiosis, one starting cell can produce four gametes (eggs or sperm). In each round of division, cells go through four stages: prophase, metaphase, anaphase, and telophase.

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Which statements apply to transverse waves? Check all that apply.

Levart [38]

Correct Answers:

- The waves have a trough

- the waves have a crest

- the energy that is transferred move in a perpendicular direction

- particles move in an up and down motion

8 0

3 years ago

Read 2 more answers

A ball on a string makes 25.0 revolutions in 9.37 s, in a circle radius 0.450 m. What is it’s velocity?

Sauron [17]

The velocity of the ball is 12.5 m/s

Explanation:

The velocity of the ball is given by the ratio between the distance covered by the ball and the time taken:

$v=\frac{d}{t}$

First, we calculate the distance covered. We know that the radius of the circle is

r = 0.450 m

And the length of the circumference is

$L=2\pi r = 2\pi(0.750)=4.7 m$

The ball makes 25.0 revolutions, so a total distance of

$d=(25.0)L=(25.0)(4.7)=117.5 m$

In a time of

t = 9.37 s

So, its velocity is

$v=\frac{117.5}{9.37}=12.5 m/s$

Learn more about velocity here:

brainly.com/question/5248528

#LearnwithBrainly

3 0

3 years ago

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Which of the following is a risk associated with taking performance-enchancing drugs.

Damm [24]

Answer:

The correct answer is All of the above.

Explanation:

7 0

3 years ago

Suppose you wish to fabricate a uniform wire out of 1.10 g of copper. If the wire is to have a resistance R = 0.390 Ω, and if al

Citrus2011 [14]

To solve this problem we will apply the concepts related to volume, as a function of length and area, as of mass and density. Later we will take the same concept of resistance and resistivity, equal to the length per unit area. Once obtained from the known constants it will be possible to obtain the area by matching the two equations:

Mass of copper wire $(m) = 1.10g = 1.10*10^{-3} kg$

Density $(\rho)= 8.92*10^3kg/m^3$

Resistively of copper $(\gamma) = 1.7*10^{-8}\Omega \cdot m$

Resistance (R) = 0.390\Omega

Volume is defined as,

$V= lA \text{ and }\frac{m}{\rho}$

$lA= \frac{1.10*10^{-3}}{8.92*10^3}$

$lA = 1.233*10^{-7} m^3$ (1)

We know that,

$\frac{l}{A} = \frac{R}{\gamma}$

$\frac{l}{A}= \frac{0.390\Omega}{1.7*10^{-8}\Omega m}$

$\frac{l}{A} = 2.2941*10^7 m^{-1}$ (2)

Multiplying equation we have

$l^2 = (1.233*10^{-7})( 2.2941*10^7)$

$l^2 = 2.8286m^2$

$l =\sqrt{2.8286m^2}$

$l = 1.68m$

Therefore the length of the wire is 1.68m

6 0

3 years ago

When a net force of 17.0 newtons is applied to a dictionary placed on a frictionless table, it accelerates by 3.75 meters/second

4vir4ik [10]

Force = (mass) x (acceleration) (Newton's second law of motion)

Divide both sides of the equation by 'acceleration', and you have

Mass = (force) / (acceleration)

Mass = 17 newtons / 3.75 meters per second-sqrd = 4.533 kilograms (rounded)

8 0

3 years ago