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babunello [35]
3 years ago
10

mike shoots a large marble (Marble A, mass:0.05 kg) at a smaller marble (Marble B, mass: 0.03 kg) that is sitting still. Marble

A was initially lacking at a velocity of 0.6 m/s, but after the collision it has a velocity of -0.2 m/s what is the resulting velocity of marble B after the collision? be sure to show your work.
Physics
1 answer:
mixas84 [53]3 years ago
7 0

Explanation:

According to Conservation of Linear Momentum :

m_1u_1+m_2u_2=m_1v_1+m_2v_2

0.05 \times 0.6 + 0.03 \times 0 = 0.05 \times  - 0.2 + 0.03 \times v_2

0.04 = 0.03v_2

Velocity of marble B after collision = 1.33 m/sec

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A 7300 kg rocket blasts off vertically from the launch pad with a constant upward acceleration of 2.20 m/s2 and feels no appreci
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Answer:

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We shall first calculate the velocity at height h = 575 m .

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v² = 0 + 2 x 2.2 x 575

v = 50.3 m /s

After 575 m , rocket moves under free fall so g will act on it downwards

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4 0
2 years ago
A camera is equipped with a lens with a focal length of 34 cm. When an object 2.4 m (240 cm) away is being photographed, what is
puteri [66]

Answer:

The magnification is -6.05.

Explanation:

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\dfrac{1}{u}+\dfrac{1}{v}=\dfrac{1}{f}

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