Question

mike shoots a large marble (Marble A, mass:0.05 kg) at a smaller marble (Marble B, mass: 0.03 kg) that is sitting still. Marble A was initially lacking at a velocity of 0.6 m/s, but after the collision it has a velocity of -0.2 m/s what is the resulting velocity of marble B after the collision? be sure to show your work.

Answer 1

Explanation:

According to Conservation of Linear Momentum :

$m_1u_1+m_2u_2=m_1v_1+m_2v_2$

$0.05 \times 0.6 + 0.03 \times 0 = 0.05 \times - 0.2 + 0.03 \times v_2$

$0.04 = 0.03v_2$

Velocity of marble B after collision = 1.33 m/sec