Answer:
the resistance of the second wire is 1 ohm.
Explanation:
Given;
cross sectional area of the first wire, A₁ = 5.00 x 10⁶ m²
resistance of the first wire, R₁ = 1.75 ohms
cross sectional area of the second wire, A₂ = 8.75 x 10⁶ m²
resistance of the second wire, R₂ = ?
The resistance of a wire is given as;
R ∝ 
Since the length of the two wires is constant
R₁A₁ = R₂A₂

Therefore, the resistance of the second wire is 1 ohm.
During either one, the sun, moon, and Earth are lined up in the same straight line. The difference is whether the moon or the Earth is the one in the "middle".
Answer:
i think its 4 or 35
Explanation:
its in the middle of 40 and 30
Sports drinks do offer some benefits when comparing sports drinks vs. water. While water actually works better at fluid replacement, sports drinks are often more appealing to the palate. In other words, people who enjoy the taste of sports drinks may drink more of a sports drink than they would water; this will lead to better hydration.
Sports drinks also contain electrolytes and carbohydrates. While exercising for short periods of time, it is not necessary to replace electrolytes; however, athletes and marathon participants exercising for period of an hour or more can benefit from electrolyte replacement in particular. Carbohydrates offer the body energy. When the body burns calories, it needs carbohydrates to replace energy lost. The longer the workout, the more carbohydrates are needed.
Answer:
α = 1.114 × 10⁻³ (°C)⁻¹
Explanation:
Given that:
Length of rod (L) = 1.5 m,
Diameter (d) = 0.55 cm,
Area (A) = 
Radius (r) = d / 2 = 0.275 cm,
Voltage across the rod (V) = 15.0 V.
At initial temperature (T₀) = 20°C, the current (I₀) = 18.8 A while at a temperature (T) = 92⁰C, the current (I) = 17.4 A
a) The resistance of the rod (R) is given as:

Therefore the resistivity and for the material of the rod at 20 °C (ρ) is:
b) The temperature coefficient of resistivity at 20°C for the material of the rod (α) can be gotten from the equation:
![R_T=R_0[1-\alpha (T-T_0)]\\but,R_T=\frac{V}{I}=\frac{15}{17.4}=0.862\\](https://tex.z-dn.net/?f=R_T%3DR_0%5B1-%5Calpha%20%28T-T_0%29%5D%5C%5Cbut%2CR_T%3D%5Cfrac%7BV%7D%7BI%7D%3D%5Cfrac%7B15%7D%7B17.4%7D%3D0.862%5C%5C)
Rearranging to make α the subject of formula:
