An atom of element X has an atomic mass of about 40; after reacting with a second atom of X, a different element (called Y) with
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Answer:
P₂ = 1.12 atm
Explanation:
To find the new pressure, you need to use the Combined Gas Law:
In this equation, "P₁", "V₁", and "T₁" represent the initial pressure, volume, and temperature. "P₂", "V₂", and "T₂" represent the new pressure, volume, and temperature. Before plugging the values into the equation, you need to
(1) convert the pressure from mmHg to atm (760 mmHg = 1 atm)
(2) convert the temperatures from Celsius to Kelvin (°C + 273)
The final answer should have 3 sig figs like the given values.
P₁ = 365 mmHg / 760 = 0.480 atm P₂ = ? atm
V₁ = 5.00 L V₂ = 2.30 L
T₁ = 20°C + 273 = 293 K T₂ = 40°C + 273 = 313 K
<----- Combined Gas Law
<----- Insert values
<----- Simplify left side
<----- Multiply both sides by 313
<----- Divide both sides by 2.30