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alexira [117]
3 years ago
9

Salt water

Chemistry
1 answer:
lidiya [134]3 years ago
5 0

Answer:

salt water heterogeneous mixture , pure substance compound,element solut8on

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How many grams of Al(OH)3 are produced from 3.00 g of AlCl3 with excess of NaOH?
Blizzard [7]

Answer:

1.772 gram is the approximate answer

Explanation:

molecular mass of AlCl3 is 132 g per mole and of Al(OH)3 is 78 g per mole

the reaction is

AlCl3 + 3 NaOH ---> Al(OH)3 + 3 NaCl

from the reaction it is clear that 1 mole AlCl3 makes 1 mole Al(OH)3

implies 132g AlCl3 gives 78g Al(OH)3

Implies 3g AlCl3 gives

3*122/78 = 1.772 grams

3 0
3 years ago
Which term defines the following: moles of solute mass of solvent in kg?
kramer
The answer is B. molality
7 0
3 years ago
Particles are arranged in a crystal structure in a sample of
Sergeu [11.5K]
The answer is (4) Ag(s)

Solid Silver has a Face Centered Cubic crystal structure.

The remaining choices are gases (H2 & Ar) and liquid (Br). Liquids and gases do not form crystal structures as their atoms are loose.
3 0
3 years ago
Under identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simulta
scoray [572]

Answer:

70.77 g/mol is the molar mass of the unknown gas.

Explanation:

Effusion is defined as rate of change of volume with respect to time.

Rate of Effusion=\frac{Volume}{Time}

Effusion rate of oxygen gas after time t = E=\frac{4.64 mL}{t}

Molar mass of oxygen gas = M = 32 g/mol

Effusion rate of unknown gas after time t = E'=\frac{3.12 mL}{t}

Molar mass of unknown gas = M'

The rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:

\text{Rate of effusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

\frac{E}{E'}=\sqrt{\frac{M'}{M}}

\frac{\frac{4.64 mL}{t}}{\frac{3.12 mL}{t}}=\sqrt{\frac{M'}{32 g/mol}}

M' = 70.77 g/mol

70.77 g/mol is the molar mass of the unknown gas.

8 0
3 years ago
How many days would it take for a crepe myrtle tree to grow 1 cm in height if it grows 3.38 feet per year?
ololo11 [35]
It's very easy, it's depending mainly on converting a mathematical unit:

When 1 Cm = 0.0328084 Ft
So, we assume that: 
in    1 year → it grows 3.38 Ft

So  X(years)→ 0.0328084

∴X(years) = 0.0328084 * 3.38 = 0.0097 year

We have to convert this unit form years to days by:

       1 year = 365 days
So,  0.0097 =  X (days)
∴X(days)= 365 * 0.0097 = 3.5 days

So it will take 3.5 days to grow up

7 0
3 years ago
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