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3 years ago

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A mixture of He He , N 2 N2 , and Ar Ar has a pressure of 24.1 24.1 atm at 28.0 28.0 °C. If the partial pressure of He He is 301

3 3013 torr and that of Ar Ar is 2737 2737 mm Hg, what is the partial pressure of N 2 N2

1 answer:

Karo-lina-s [1.5K]3 years ago

8 0

Answer:

16.5 atm

Explanation:

<em>A mixture of He, N₂, and Ar has a pressure of 24.1 atm at 28.0 °C. If the partial pressure of He is 3013 torr and that of Ar is 2737 mm Hg, what is the partial pressure of N₂?</em>

The total pressure of a gaseous mixture is equal to the sum of the partial pressures.

P = pHe + pN₂ + pAr

pN₂ = P - pHe - pAr [1]

We need to express pHe and pAr in atm.

$pHe=3013torr.\frac{1atm}{760torr} =3.96atm$

$pAr=2737mmHg.\frac{1atm}{760mmHg} =3.60atm$

From [1],

pN₂ = 24.1 atm - 3.96 atm - 3.60 atm = 16.5 atm

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