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3 years ago

Which is a correct step in a scientific experiment involving acids and bases?

Physics

1 answer:

yuradex [85]3 years ago

6 0

Answer:

b) using an indicator to measure the hydrogen ion concentration of a solution

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A sound wave travels through water. What best describes the direction of the water particles?

balu736 [363]

Answer:

In water, the particles are much closer together, and they can quickly transmit vibration energy from one particle to the next.

A water wave is an example of a transverse wave. As water particles move up and down, the water wave itself appears to move to the right or left.

7 0

3 years ago

EXERCISE 1

denpristay [2]

.........The answer is A

5 0

2 years ago

A convex mirror has a focal length of -12 cm. A lightbulb with

horrorfan [7]

Answer:

PLEASE MARK AS BRAINLIEST!!

Explanation:

ANSWER IS IN THE IMG BELOW

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2 years ago

A 16.2 kg person climbs up a uniform ladder with negligible mass. The upper end of the ladder rests on a frictionless wall. The

S_A_V [24]

To solve this problem we will apply the concepts related to the balance of forces. We will decompose the forces in the vertical and horizontal sense, and at the same time, we will perform summation of torques to eliminate some variables and obtain a system of equations that allow us to obtain the angle.

The forces in the vertical direction would be,

$\sum F_x = 0$

$f-N_w = 0$

$N_w = f$

The forces in the horizontal direction would be,

$\sum F_y = 0$

$N_f -W =0$

$N_f = W$

The sum of Torques at equilibrium,

$\sum \tau = 0$

$Wdcos\theta - N_wLsin\theta = 0$

$WdCos\theta = fLSin\theta$

$f = \frac{Wd}{Ltan\theta}$

The maximum friction force would be equivalent to the coefficient of friction by the person, but at the same time to the expression previously found, therefore

$f_{max} = \mu W=\frac{Wd}{Ltan\theta}$

$\theta = tan^{-1} (\frac{d}{\mu L})$

Replacing,

$\theta = tan^{-1} (\frac{0.9}{0.42*2})$

$\theta = 46.975\°$

Therefore the minimum angle that the person can reach is 46.9°

8 0

3 years ago

When an athlete holds a barbell overhead, the reaction force is the weight of the barbell on his hand. how does this force vary

Sonja [21]

The force applied by the competitor is littler than the heaviness of the barbell. At the point when the barbell quickens upward, the power applied by the competitor is more prominent than the heaviness of the barbell. When it decelerates upward, the power applied by the competitor is littler than the heaviness of the barbell.

3 0

3 years ago