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Lunna [17]
3 years ago
10

A 600W toaster, 1200W iron and a 100W bulb are all connected to household 120V circuit. a) find the current drawn by each applia

nce
b) the resistance of the heating element in the iron
c) the total cost of running all of the appliances non-stop for 5 days if the electricity rate is $0.1 per KW-Hr.
Physics
2 answers:
Advocard [28]3 years ago
8 0

Answer:

(a) %a, 10 A, 0.833 A

(b) 12 ohm

(c) $22.8

Explanation:

Power of toaster, P1 = 600 W

Power of iron, P2 = 1200 W

Power of bulb, P3 = 100 W

V = 120 V

As they are in household circuit, so they are connected in parallel, so the voltage is same for all.

(a) Use the formula P = V x i

Current in toaster, i1 = P1 / V = 600 / 120 = 5 A

Current in iron, i2 = P2 / V = 1200 / 120 = 10 A

Current in bulb, i3 = P3 / V = 100 / 120 = 0.833 A

(b) Resistance of heating element of iron is R2.

V = i2 x R2

120 = 10 x R2

R2 = 12 ohm

(c) Total energy consumed in 24 hours for 5 days

                              = (600 + 1200 + 100) x 24 x 5 = 228000 Wh = 228 KWh

Cost of 1 KWh = $0.1

Cost of 228 KWh = 0.1 x 228 = $22.8

den301095 [7]3 years ago
3 0

_______________________________

Answer:

(a). Toaster = 5A

Iron = 10A

Bulb = 0.833A

(b). R2 = 12Ω

(c). $ 22.8

_______________________________

Explanation:

<u>Given</u>,

Power of Toaster, P1 = 600W

Power of Iron, P2 = 1200W

Power of Bulb, P3 = 100W

Potential difference = 120V

<u>T</u><u>hey all are connected in parallel combination because they all are household circuits so that the voltage is same for all appliances in the circuit</u><u>.</u>

★<u>Solu</u><u>tion</u><u> of</u><u> </u><u>(</u><u>a</u><u>)</u>

<u>B</u><u>y using the formula of power</u><u> </u><u>we can find out the current</u><u>.</u>

<h3> P = V × I</h3>

Here, power is directly proportional to the potential difference and electric current flowing through the circuit.

<h3>[ .°. I = P / V ]</h3>

<u>H</u><u>ere</u><u>,</u><u> </u><u>e</u><u>l</u><u>e</u><u>c</u><u>t</u><u>r</u><u>i</u><u>c</u><u> </u><u>current</u><u> is </u><u>inver</u><u>se</u><u>ly proportional to the potential difference</u><u> </u><u>and</u><u> </u><u>electri</u><u>c</u><u> current</u><u> </u><u>is</u><u> </u><u>dir</u><u>ectly</u><u> proportional</u><u> to</u><u> </u><u>power</u><u>.</u>

Current in Toaster, I1 = P1/V = 600/120 = 5A

Current in Iron, I2 = P1/V = 1200/120 = 10A

Current in Bulb, I3 = P1/V = 100/120 = 0.833A

★<u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>of</u><u> </u><u>(</u><u>b</u><u>)</u>

Resistance of Heating coil of Iron

<u>B</u><u>y using the</u><u> </u><u>formula of Ohm's Law we can find out the resistance of heating</u><u> </u><u>coil of </u><u>iron</u><u>.</u>

<h3>V = I × R</h3>

Here, the potential difference is directly proportional to the current carrying wire and potential difference is directly proportional to the resistance off the wire present in the Iron.

<h3>[ .°. R = V/I ]</h3>

Here, resistance is directly proportional to the potential difference and resistance is inversely proportional to the electric current.

R = V/I

=> R = 120/10

.°. R = 12Ω

★<u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>of</u><u> </u><u>(</u><u>c</u><u>)</u>

Total consumption of Energy in 24 hours for 5 days = (600W + 1200W + 100W) × 24 hours × 5 days

= 228000Wh

= 228kWh

When the cost of 1kWh = $ 0.1

So,

The cost of 228 kWh = $ 0.1 × 228 = $ 22.8

_______________________________

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