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Answer:
(a). Toaster = 5A
Iron = 10A
Bulb = 0.833A
(b). R2 = 12Ω
(c). $ 22.8
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Explanation:
<u>Given</u>,
Power of Toaster, P1 = 600W
Power of Iron, P2 = 1200W
Power of Bulb, P3 = 100W
Potential difference = 120V
<u>T</u><u>hey all are connected in parallel combination because they all are household circuits so that the voltage is same for all appliances in the circuit</u><u>.</u>
★<u>Solu</u><u>tion</u><u> of</u><u> </u><u>(</u><u>a</u><u>)</u>
<u>B</u><u>y using the formula of power</u><u> </u><u>we can find out the current</u><u>.</u>
<h3>
P = V × I</h3>
Here, power is directly proportional to the potential difference and electric current flowing through the circuit.
<h3>
[ .°. I = P / V ]</h3>
<u>H</u><u>ere</u><u>,</u><u> </u><u>e</u><u>l</u><u>e</u><u>c</u><u>t</u><u>r</u><u>i</u><u>c</u><u> </u><u>current</u><u> is </u><u>inver</u><u>se</u><u>ly proportional to the potential difference</u><u> </u><u>and</u><u> </u><u>electri</u><u>c</u><u> current</u><u> </u><u>is</u><u> </u><u>dir</u><u>ectly</u><u> proportional</u><u> to</u><u> </u><u>power</u><u>.</u>
Current in Toaster, I1 = P1/V = 600/120 = 5A
Current in Iron, I2 = P1/V = 1200/120 = 10A
Current in Bulb, I3 = P1/V = 100/120 = 0.833A
★<u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>of</u><u> </u><u>(</u><u>b</u><u>)</u>
Resistance of Heating coil of Iron
<u>B</u><u>y using the</u><u> </u><u>formula of Ohm's Law we can find out the resistance of heating</u><u> </u><u>coil of </u><u>iron</u><u>.</u>
<h3>
V = I × R</h3>
Here, the potential difference is directly proportional to the current carrying wire and potential difference is directly proportional to the resistance off the wire present in the Iron.
<h3>
[ .°. R = V/I ]</h3>
Here, resistance is directly proportional to the potential difference and resistance is inversely proportional to the electric current.
R = V/I
=> R = 120/10
.°. R = 12Ω
★<u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>of</u><u> </u><u>(</u><u>c</u><u>)</u>
Total consumption of Energy in 24 hours for 5 days = (600W + 1200W + 100W) × 24 hours × 5 days
= 228000Wh
= 228kWh
When the cost of 1kWh = $ 0.1
So,
The cost of 228 kWh = $ 0.1 × 228 = $ 22.8
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