A. Bc a negative times a negative would be positive
C. Bc it would equal 0 and zero is not negative.
1*-7=-7 it wants a negative value so times it by one keeps it negative and same with if it is Multiplied by 7
Answer:
G(x,y)=(-4,0)
Step-by-step explanation:
We use the section formula:
Given:
We substitute the values to get:
Answer:
See below
Step-by-step explanation:
13*1 = 13
13*2 = 26
13*3 = 39
13*4 = 52
13*5 = 65
13*6 = 78
13*7 = 91
13*8 = 104
13*9 = 117
13*10 = 130
Answer:
there is no collision between the particles
Step-by-step explanation:
for the first particle
x1=3sin t, y1 = 2 cos t, 0 ≤ t ≤ 2π
for the second particle
x2 = -3 + cos t, y2 = 1 + sin t, 0 ≤ t ≤ 2π
then for the collision
x1=x2 → 3*sin t = -3 + cos t → sin t= -1 + (cos t)/3→ 1+ sin t = (1/3)cos t
y1=y2 → 1 + sin t = 2 cos t → (1/3)cos t = 2 cos t →(1/3) = 2
since 1/3 ≠ 2 there is no collision between the particles
