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dem82 [27]
3 years ago
13

Solve the x 1/3x + 5> 10

Mathematics
1 answer:
kotykmax [81]3 years ago
5 0

Answer:

The solution to the inequality is:

\frac{1}{3}x+5>10\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x>15\:\\ \:\mathrm{Interval\:Notation:}&\:\left(15,\:\infty \:\right)\end{bmatrix}

The solution graph is also attached below.

Step-by-step explanation:

Given

We are given the expression

\frac{1}{3}x+5>10

To determine

Solve for x

Given the expression

\frac{1}{3}x+5>10

Subtract 5 from both sides

\frac{1}{3}x+5-5>10-5

Simplify

\frac{1}{3}x>5

Multiply both sides by 3

3\cdot \frac{1}{3}x>5\cdot \:3

Simplify

x>15

Thus, we conclude that:

x>15

Therefore, the solution to the inequality is:

\frac{1}{3}x+5>10\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x>15\:\\ \:\mathrm{Interval\:Notation:}&\:\left(15,\:\infty \:\right)\end{bmatrix}

The solution graph is also attached below.

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Answer:

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Step-by-step explanation:

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3 years ago
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Answer: -2/3x+/2/5

Step-by-step explanation:

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Read 2 more answers
if alpha and beta are the roots of the equation 3x^2-9x+2=0 find the values of: (I) alpha ×beta + alpha^2 × beta. (ii) alpha^2-a
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Answer:

in steps

Step-by-step explanation:

The question did not state if alpha>beta or alpha<beta, so the answer will have 2 answers  for each questions

3x²-9x+2=0

x = (-(-9) ± √(-9)²-4*(3)*(2)) / (2*3)

x = (9 + √57) / 6   or x = (9 - √57) / 6      (alpha and beta) or (beta and alpha)

(I) alpha (a) ×beta (b) + alpha² × beta = ab (1+a)

   = ((9 + √57) / 6) ((9 - √57) / 6) (1 + (9 ± √57))  

   = ((9² - (√57)²)/36) (10 ± √57)

   = (24/36) (10 ± √57)

   = 2/3 (10 ± √57)   or (11.7 or 1.63)

(ii) alpha²-alpha×beta+beta² = a² -2ab + b² +ab = (a - b)² + ab

if a is alpha    

=​ ((9 + √57) / 6) - ((9 - √57) / 6)) + ((9 + √57) / 6) ((9 - √57) / 6))  

    = √57/3 + 2/3

     = (√57 + 2) / 3

if a is beta

((9 - √57) / 6) - ((9 + √57) / 6)) + ((9 - √57) / 6) ((9 + √57) / 6))  

    = - √57/3 + 2/3

     = - (√57 + 2) / 3

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Answer:

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