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Scorpion4ik [409]
2 years ago
11

SOME ONE PLZ HELP WILL GIVE THE BRAINIEST

Physics
1 answer:
Keith_Richards [23]2 years ago
4 0

Answer:

I. 90%

II. 60 MW

Explanation:

From the question given above, the following data were obtained:

Power input = 600 MW

Power output = 540 MW

I. Determination of the efficiency.

Power input = 600 MW

Power output = 540 MW

Efficiency =?

Efficiency = output / input × 100

Efficiency = 540 / 600 × 100

Efficiency = 90%

II. Determination of the power wasted by the pump.

Power input = 600 MW

Power output = 540 MW

Power wasted =?

Power wasted = Power input – Power output

Power wasted = 600 – 540

Power wasted = 60 MW

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A. lunar phases result from the changing lunar mass. Let me know if this helped.
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3 years ago
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6. A golf ball is hit a distance of 300 yards in 10 sec. What is the speed of the golf ballo
katen-ka-za [31]

The speed of the ball is 27.4 m/s

Explanation:

The speed of an object is given by:

speed=\frac{d}{t}

where

d is the distance covered

t is the time taken

In this problem, we have:

d = 300 yards is the distance covered by the golf ball

t = 10 s is the time taken

Keeping in mind that

1 yard = 0.914 m

We can convert the distance from yards to meters:

d = 300 \cdot 0.914 = 274.2 m

And substituting into the equation, we find the speed of the ball:

speed=\frac{274.2}{10}=27.4 m/s

Learn more about speed:

brainly.com/question/8893949

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3 0
2 years ago
A typical cell phone charger is rated to transfer a maximum of 1.0 Coulomb of charge per second. Calculate the maximum number of
Alexandra [31]

Answer:

The maximum no. of electrons- 2.25\times 10^{22}

Solution:

As per the question:

Maximum rate of transfer of charge, I = 1.0 C/s

Time, t = 1.0 h = 3600 s

Rate of transfer of charge is current, I

Also,

I = \frac{Q}{t}

Q = ne

where

n = no. of electrons

Q = charge in coulomb

I = current

Thus

Q = It

Thus the charge flow in 1. 0 h:

Q = 1.0\times 3600 = 3600\ C

Maximum number of electrons, n is given by:

n = \frac{Q}{e}

where

e = charge on an electron = 1.6\times 10^{- 19}\ C

Thus

n = \frac{3600}{1.6\times 10^{- 19}} = 2.25\times 10^{22}

3 0
3 years ago
Sinisimulan ko<br> Kaya Ko<br> Gagawin ko<br> Nalaman ko<br> Natututo Ako
ozzi

Answer:

what!!!!!!

Explanation:

didn't got the point

7 0
3 years ago
A student finds an unlabeled liquid container in his lab. He notices that the container has two liquids. Since the two liquids h
raketka [301]

Answer:

\rho = 1848.03 kg m^{-3}

Explanation:

given data:

density of water \rho = 1 gm/cm^3 = 1000 kg/m^3

height  of water  = 20 cm  =0.2 m

Pressure  p = 1.01300*10^5 Pa

pressure at bottom

P =  P_{fluid} + P_{h_2 o}

P   = P_{fluid}  + \rho g h

P_{fluid}  = P - \rho g h

                 = 1.01300*10^5 - 1000*0.2*9.8

                 = 99340 Pa

p_{fluid}  = P_{atm} + \rho g h_{fluid}                       h_[fluid} = 0.307m

99340 = 104900 + \rho *9.8*0.307

\rho = 1848.03 kg m^{-3}

5 0
3 years ago
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