It would <span>keep rolling without slowing down if no friction acted upon it.
</span>
Answer:
(a) ![\lambda=1.227\ A](https://tex.z-dn.net/?f=%5Clambda%3D1.227%5C%20A)
(b) ![\lambda=0.388\ A](https://tex.z-dn.net/?f=%5Clambda%3D0.388%5C%20A)
(c) ![\lambda=0.038\ A](https://tex.z-dn.net/?f=%5Clambda%3D0.038%5C%20A)
Explanation:
Given that,
(a) An electron accelerated from rest through a potential difference of 100 V. The De Broglie wavelength in terms of potential difference is given by :
![\lambda=\dfrac{h}{\sqrt{2meV} }](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7Bh%7D%7B%5Csqrt%7B2meV%7D%20%7D)
Where
m and e are the mass of and charge on an electron
On solving,
![\lambda=\dfrac{12.27}{\sqrt{V} }\ A](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7B12.27%7D%7B%5Csqrt%7BV%7D%20%7D%5C%20A)
V = 100 V
![\lambda=\dfrac{12.27}{\sqrt{100} }\ A](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7B12.27%7D%7B%5Csqrt%7B100%7D%20%7D%5C%20A)
![\lambda=1.227\ A](https://tex.z-dn.net/?f=%5Clambda%3D1.227%5C%20A)
(b) V = 1 kV = 1000 V
![\lambda=\dfrac{12.27}{\sqrt{V} }\ A](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7B12.27%7D%7B%5Csqrt%7BV%7D%20%7D%5C%20A)
![\lambda=\dfrac{12.27}{\sqrt{1000} }\ A](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7B12.27%7D%7B%5Csqrt%7B1000%7D%20%7D%5C%20A)
![\lambda=0.388\ A](https://tex.z-dn.net/?f=%5Clambda%3D0.388%5C%20A)
(c) If ![V=100\ kV=10^5\ V](https://tex.z-dn.net/?f=V%3D100%5C%20kV%3D10%5E5%5C%20V)
![\lambda=\dfrac{12.27}{\sqrt{10^5} }\ A](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7B12.27%7D%7B%5Csqrt%7B10%5E5%7D%20%7D%5C%20A)
![\lambda=0.038\ A](https://tex.z-dn.net/?f=%5Clambda%3D0.038%5C%20A)
Hence, this is the required solution.
B. picking up a box off the floor
<span> this would be most affected Coriolis effect. </span>
Like all experiments, it's important to keep records of the their experiment procedures so future car designers and experimenters can compare and contrast their results from their experiment and improve their experiment accordingly. I'm pretty sure this is it. Stay cool my man.