What force is required to accelerate a 1840 kg car from 4.77 m/s to 23.5 m/s,
1 answer:
A :-) for this question , we should apply a = v - u by t Given - u = 4.77 m/s v = 23.5 m/s t = 5.18 m/s Solution - a = v - u by t a = 23.5 - 4.77 a = 28.27 m/s^2 .:. The acceleration is 28.27 m/s^2
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