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3 years ago

Identify this reaction HBr+ Al(OH)3 —-> H2O + AlBr3

Chemistry

1 answer:

Vikki [24]3 years ago

5 0

<h2><em><u>Answer</u></em></h2>

Neutralization reaction

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One calcium atom for every two iodine atoms chemical formula

borishaifa [10]

Is it multiple choice or do you just answer

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3 years ago

Problem PageQuestion Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume

IgorC [24]

Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume of hydrogen chloride would be produced by this reaction if 3.16 L of chlorine were consumed at STP.

Be sure your answer has the correct number of significant digits.

Answer: Thus volume of carbon tetrachloride that would be produced is 0.788 L

Explanation:

According to ideal gas equation:

$PV=nRT$

P = pressure of gas = 1 atm (at STP)

V = Volume of gas = 3.16 L

n = number of moles = ?

R = gas constant = $0.0821Latm/Kmol$

T =temperature = $273K=$

$n=\frac{PV}{RT}$

$n=\frac{1atm\times 3.16L}{0.0820 L atm/K mol\times 273K}=0.141moles$

$CH_4+4Cl_2\rightarrow 4HCl+CCl_4$

According to stoichiometry:

4 moles of chlorine produces = 1 mole of carbon tetrachloride

Thus 0.141 moles of methane produces = $\frac{1}{4}\times 0.141=0.0352$ moles of carbon tetrachloride

volume of carbon tetrachloride = $moles\times {\text {Molar volume}}=0.0352mol\times 22.4L/mol=0.788L$

Thus volume of carbon tetrachloride that would be produced is 0.788 L

8 0

4 years ago

A binding protein binds to a ligand l with a kd of 400 nm what is the concentration of ligand when y is 0.25

vampirchik [111]

Answer:

The answer is 7600 nm.

Explanation:

As, Y = 0.25 = [ L ÷ (400 + (L)]

0.95 x 400 + 0.25 [ L] = [ L ]

380.25 = [ L ] - 0.95 [ L ]

= 0.05 [L]

[L] = 380 ÷ 0.05 = 7600nm

6 0

3 years ago

How many grams of NaOH are produced from 1.20 x 10^2 of Na2O

oksian1 [2.3K]

Write an balance the equation

Na2O + H2O -> 2 NaOH

Calculate the molecular mass of Na2O and NaOH from the atomic mass from the periodic table.

Na = 23
O=16
H=1

Na2O = 23 * 2 + 16 = 62
NaOH = 23+16+1= 40

For the stoichiometry of the reaction one mole of Na2O = 62g produce two mol of NaOH = 2* 40= 80 g

120 g Na2O x 80g NaOH / 62g Na2O=

154.8 g NaOH

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4 years ago

Why are these graphs misleading

ch4aika [34]

Although there isn’t a picture a graph can be misleading when it doesn’t start at zero, it doesn’t give accurate information, it skips too many numbers, the vertical scale is too big or too small. Hope this helps

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3 years ago