Answer:
The amount of water converted from liquid to gas with 6,768 joules is approximately 3.035 g
Explanation:
The amount of heat required to convert a given amount of liquid to gas at its boiling point is known as the latent heat of evaporation of the liquid
The latent heat of evaporation of water, Δ
≈ 2,230 J/g
The relationship between the heat supplied, 'Q', and the amount of water in grams, 'm', evaporated is given as follows
Q = m × Δ
Therefore, the amount of water, 'm', converted from liquid to gas at the boiling point temperature (100°C), when Q = 6,768 Joules, is given as follows;
6,768 J = m × 2,230 J/g
∴ m = 6,768 J /(2,230 J/g) ≈ 3.035 g
The amount of water converted from liquid to gas with 6,768 joules = m ≈ 3.035 g.
A) Magnesium + Chlorine -> Magnesium chloride ( Mg + Cl2 -> MgCl2)
b) Potassium + Oxygen -> Potassium oxide
( 2K + O2 -> K2O )
c) Sodium + Bromine -> Sodium bromide
( 2Na + Br2 -> 2NaBr)
d) Carbon + Oxygen -> Carbon dioxide
( C + O2 -> CO2 ) This reaction occurs when heated.
Answer:
This means that the metal is more properly viewed as an array of positive ions surrounded by a “sea of mobile valence electrons.” Electrons which are capable of moving freely throughout the empty orbitals of the metallic crystal are called delocalized electrons (Figure below).
Electronnegativity increase because the number of charges on the nucleus increases. Which attracts the bonding amount of electrons more.
Answer:
A
Explanation:
There is a specific tool called an oil drill that drills into the ground and then a pipe sucks the oil up onto a vessle
