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jasenka [17]
2 years ago
15

A block of metal has a volume of 14.0in3 and weighs 5.16 lb .

Chemistry
1 answer:
riadik2000 [5.3K]2 years ago
5 0

The density of metal block in grams per cubic centimeter is 10.70 g/cm³.

Given,

Mass of metal block = 5.16 lb  

1 lb = 453.592 g

5.26 lb = 2340.536 g

The volume of metal block = 14 in 3

1 in = 2.5 cm

1 in 3 = 15.625 cm³

14 in 3 = 218.75 cm³

Density is defined as the mass per unit volume of a substance. Or, it is the ratio of mass to the volume of the substance.

As we know,

Density = mass/volume

Or, density = 2340.536 / 218.75

Or, density = 10.70 g/cm³

Therefore, the density of the metal block is 10.70 g/cm³.

To learn more about the density, visit: brainly.com/question/15164682

#SPJ9

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Explain why the following medicines should not be thrown down the drains
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Identify whether longhand notation or noble-gas notation was used in each case below.
n200080 [17]

Answer:

The given electronic configuration is long hand notation.

Explanation:

Long-hand notation of representing electronic configuration is defined as the arrangement of total number of electrons that are present in an element.

Noble-gas notation of representing electronic configuration is defined as the arrangement of valence electrons in the element. The core electrons are represented as the previous noble gas of the element that is considered.

The given electronic configuration of potassium (K):  

The above configuration has all the electrons that are contained in the nucleus of an element. Thus, this configuration is a long-hand notation.

6 0
3 years ago
Refer to the periodic table tool and write the electron configurations of the following elements in both long and short terms
ahrayia [7]

Answer:-

Carbon

[He] 2s2 2p2

1s2 2s2 2p2.

potassium

[Ar] 4s1.

1s2 2s2 2p6 3s2 3p6 4s1

Explanation:-

For writing the short form of the electronic configuration we look for the nearest noble gas with atomic number less than the element in question. We subtract the atomic number of that noble gas from the atomic number of the element in question.

The extra electrons we then assign normally starting with using the row after the noble gas ends. We write the name of that noble gas in [brackets] and then write the electronic configuration.

For carbon with Z = 6 the nearest noble gas is Helium. It has the atomic number 2. Subtracting 6 – 2 we get 4 electrons. Helium lies in 1st row. Starting with 2, we get 2s2 2p2.

So the short term electronic configuration is [He] 2s2 2p2

Similarly, for potassium with Z = 19 the nearest noble gas is Argon. It has the atomic number 18. Subtracting 19-18 we get 1 electron. Argon lies in 3rd row. Starting with 4, we get 4s1.

So the short electronic configuration is [Ar] 4s1.

For long term electronic configuration we must write the electronic configuration of the noble gas as well.

So for Carbon it is 1s2 2s2 2p2.

For potassium it is 1s2 2s2 2p6 3s2 3p6 4s1

5 0
3 years ago
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