1) As can be seen from any 1H NMR chemical shift ppm tables, hydrogens which have δ values from 2ppm to 2.3ppm are hydrogens from carbon which is bonded to a carbonyl group. From this, we can conclude that our hydrogens belong to the type, but from 2 different alkyl groups because of 2 different signals.
2) So, one alkyl group is CH3 and second one can be CH or CH2.
3) If we know that ratio between two types of hydrogens is 3:2, it can be concluded that second alkyl group is CH2.
4) Finally, we don't have any other signals and it indicates that part of the compound which continues on CH2 is exactly the same as the first part.
The ratio remains the same, 3:2 ie 6:4
Missing question:
<span>(1) C2H5OH (3) C12H22O11
(2) C6H12O6 (4) CH3COOH.
Answer is: 4) CH</span>₃COOH, acetic acid.
In water, acetic acid dissociates on ions, so it can conduct electricity:
CH₃COOH(aq) ⇄ CH₃COO⁻(aq) + H⁺(aq).
When we put
electrodes (cathode and anode) in acetic acid solution, positive and negative
ions migrate to electrodes.<span>
Negative acetate ions go to positive electrode
and gives electrons to electrode.
<span>Positive hydrogen ions go to negative electrode
and gain electrons.</span></span>
D) It is unlikely that a specific cause can be determined, but the treatment would likely be the same in either case
Answer: lone pair of electrons
Explanation: A bonding electron domain is a pair of electrons shared between two atoms and a nonbonding is a lone pair of electrons
