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coldgirl [10]
3 years ago
14

An element cannot be broken down into other substances by chemical or physical means. But you can still split a sample of an ele

ment into smaller pieces. For example, a piece of aluminum foil can be cut in half and then in half again, and all of the pieces will still be aluminum.
What do you think will eventually happen if you could continue dividing that piece of aluminum foil?


HELPPPP MEEEEEE PLZZZZZZZ!!!

I'M CRYING!
Chemistry
2 answers:
Art [367]3 years ago
5 0

Answer:

Tearing aluminum is a physical change because when u rip the paper the composition is still the same because you can always get that same piece of foil back. For example if you burn that piece of paper it will become a new substance which means you cannot get that same piece back so it would become a chemical change.

irinina [24]3 years ago
5 0

Answer:

You will reach the smallest possible piece of the aluminum.

Explanation:

You will not be able to physically separate the aluminum into two smaller elements; aluminum is already a pure elemental substance. It will not divide forever, at some point it will be as small as you can possibly make it. However, you won't be able to erase the matter completely -- it will just become very very small!

Hope this helps. brainliest plz?

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Compute the percent ionic character of the interatomic bonds for the following compounds : a. TiO2 b. ZnTe c. CsCld. InSb e. MgC
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a. 63.2%

b. 11.7%

c. 73.3%

d. 0.995%

e. 55.5%

Explanation:

An ionic compound is a compound that is formed by ions, so one of the elements must donate electrons (which is the cation, the positive ion), and the other will receive these electrons (which is the anion, the negative ion).

The power of an element has to attract the electrons is called electronegativity, and so, as higher is the difference of electronegative of the elements, it is more probable that one of them will "still" the electrons and will form an ionic compound. The percent of this ionic character can be found by the Pauling's equation:

%IC = (1 - e^{-0.25*(x_A - x_B)^2}) *100%

Where x_A - x_B is the electronegativity difference of the elements. Thus, consulting an electronegativity table:

a. x_{Ti} = 1.5

x_{O} = 3.5

%IC = (1 - e^{-0.25*(3.5 - 1.5)^2})*100%

%IC = 63.2%

b. x_{Zn} = 1.6

x_{Te} = 2.1

%IC = (1 - e^{-0.25*(2.1 - 1.6)^2})*100%

%IC = 11.7%

c. x_{Cs} = 0.7

x_{Cl} = 3.0

%IC = (1 - e^{-0.25*(3.0 - 0.7)^2})*100%

%IC = 73.3%

d. x_{In} = 1.7

x_{Sb} = 1.9

%IC = (1 - e^{-0.25*(1.9 - 1.7)^2})*100%

%IC = 0.995 %

e. x_{Mg} = 1.2

x_{Cl} = 3.0

%IC = (1 - e^{-0.25*(3.0 - 1.2)^2})*100%

%IC = 55.5%

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