What is an aqueous solution compound
1 answer:
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Answer:
Structure in attachment.
Explanation:
The oxymercuration-demercuration of an asymmetric alkene usually produces the Markovnikov orientation of an addition. The electrophile ⁺Hg(OAc), formed by the electrophile attack of the mercury ion, remains attached to least substituted group at the end of the double bond. This electrophile has a considerable amount of positive charge on its two carbon atoms, but there is more positive charge on the more substituted carbon atom, where it is more stable. The water attack occurs on this more electrophilic carbon, and the Markovnikov orientation occurs.
In hydroboration, borane adds to the double bond in one step. Boron is added to the less hindered and less substituted carbon, and hydrogen is added to the more substituted carbon. The electrophilic boron atom adds to the less substituted end of the double bond, positioning the positive charge (and the hydrogen atom) at the more substituted end. The result is a product with the anti-Markovnikov orientation.
The answer is 7.
The equivalence point of a titration is when moles of titrant added becomes equal to the moles of sample analyte.
Calculate the pH at equivalence point for a strong acid and strong base reaction.
- The given acid is HCl which is a strong acid and the base NaOH is also a strong base.
- Calculate the moles of acid HCl:
Molarity of = 0.100 M
Volume of = 50 mL = 0.050 L
×
×
- At equivalence point, same moles of base are added and thus it results into complete neutralization. Thus, all the hydrogen ions of acid are neutralized by the hydroxide ions of the base forming only water and neutral salt.
- Thus, the pH at the equivalence point becomes 7 (neutral solution).
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