Question

A wye-connected load has a voltage of 480v applied to it. What is the voltage drop across each phase

Answer 1

Answer:

$Y_A=277.128 \angle 30v$

$Y_B=277.128 \angle (-150)v$

$Y_C=277.128 \angle (90)v$

Explanation:

From the question we are told that

Voltage $V_L_L =480v$

Generally in a case of Y_connection $V_p_ h$ is mathematical represented as

$V_p_h=\frac{V_l_l}{\sqrt{3}} \angle (\phi-30)v$

Generally voltage drop across phase A

$Y_A=\frac{408}{\sqrt{3}} \angle -(0-30)$

$Y_A=277.128 \angle 30v$

Generally voltage drop across phase B

$Y_B=277.128 \angle (-30-120)$

$Y_B=277.128 \angle (-150)v$

Generally voltage drop across phase C

$Y_C=277.128 \angle (-30+120)$

$Y_C=277.128 \angle (90)v$