Answer:
(a) 185 N/m
(b) 3.083 kg
Explanation:
(a)
Using,
E = 1/2ke²....................... Equation 1
Where E = work done to compress the spring, k = spring constant of the spring, e = compression of the spring.
make k the subject of the equation
k = 2E/e²............... Equation 2
Given: E = 3.7 J, e = 0.20 m
Substitute into equation 2
k = 2(3.7)/0.2²
k = 185 N/m.
(b)
Using,
F = ma.............. Equation 2
Where F = force applied to the spring, m = mass attached to the spring, a = acceleration of the spring.
But from hook's law,
F = ke................. Equation 3
substitute equation 3 into equation 2
ke = ma
make m the subject of the equation
m = ke/a................ Equation 4
Given: k = 185 N/m, e = 0.2 m, a = 12 m/s²
Substitute into equation 4
m = 185(0.2)/12
m = 3.083 kg
