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Pie
3 years ago
9

Please help me with this

Mathematics
1 answer:
Debora [2.8K]3 years ago
3 0

9514 1404 393

Answer:

  92°

Step-by-step explanation:

The "givens" tell you the E and F are midpoints of their respective segments. That means EF ║ AB and angles DBF and EFC are "corresponding" angles with respect to transversal BC and those parallel lines. Corresponding angles are congruent, so ...

  m∠DBF = m∠EFC = 92°

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I’ll give you all stars
Lesechka [4]

Answer:

∠ HCF = 108°

Step-by-step explanation:

∠ ABG and ∠ HCF are alternate exterior angles and are congruent, thus

12x = 11x + 9 ( subtract 11x from both sides )

x = 9

Thus

∠ HCF = 11x + 9 = 11(9) + 9 = 99 + 9 = 108°

4 0
3 years ago
I don’t know how to do the problem
ahrayia [7]
Gotta move that b to the side ya dig
5 0
3 years ago
For questions 8 – 14, use the following functions:
pogonyaev

we are given

f(x)=5

g(x)=\sqrt{x+2}

(8)

(f+g)(x)=f(x)+g(x)

we can plug it

(f+g)(x)=5+\sqrt{x+2}

(9)

(f-g)(x)=f(x)-g(x)

we can plug it

(f-g)(x)=5-\sqrt{x+2}

(10)

(f*g)(x)=f(x)*g(x)

we can plug it

(f*g)(x)=5\sqrt{x+2}

(11)

(\frac{f}{g} )(x)=\frac{f(x)}{g(x)}

we can plug it

(\frac{f}{g} )(x)=\frac{5}{\sqrt{x+2}}

(12)

(\frac{g}{f} )(x)=\frac{g(x)}{f(x)}

we can plug it

(\frac{g}{f} )(x)=\frac{\sqrt{x+2}}{5}

(13)

(fog)(x)=f(g(x))

f(x)=5

we can replace g(x)

we get

(fog)(x)=5

(14)

(gof)(x)=g(f(x))

f(x)=5

we can replace f(x)

(gof)(x)=\sqrt{f(x)+2}

we get

(gof)(x)=\sqrt{5+2}

(gof)(x)=\sqrt{7}


8 0
3 years ago
The number of violent crimes committed in a day possesses a distribution with a mean of 2.2 crimes per day and a standard deviat
VARVARA [1.3K]

Answer:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And replacing we got:

\mu_{\bar X}= 2.2

\sigma_{\bar X}= \frac{6}{\sqrt{100}}= 0.6

Step-by-step explanation:

For this case we have the following info given:

\mu = 2.2 represent the mean

\sigma = 6 represent the deviation

We select a sample size of n=100. This sample is >30 so then we can use the central limit theorem. And we want to find the distribution for the sample mean and we know that the distribution is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And replacing we got:

\mu_{\bar X}= 2.2

\sigma_{\bar X}= \frac{6}{\sqrt{100}}= 0.6

6 0
4 years ago
Expression that equals 118
Andrei [34K]
Here are the following multiples:
59 * 2 = 118

and 118 * 1 = 118

The * means times.
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3 years ago
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