Answer:
1) Rick should be taking and gathering the gas with his hand towards his face gently to get just a whiff.
2) These students are doing the complete opposite of what should properly be done. Andrew shouldn't be drinking any chemicals that don't belong in his body. Sarah shouldn't be throwing whatever chemicals into a mixture, this can cause a lot of possible danger. Rick shouldn't be directly smelling the gas which can also be harmful. Rick needs to be wearing gloves and smell the gas in a proper way. Sarah should wear goggles and pay attention to what she is mixing. Andrew should be wearing gloves and goggles and shouldn't be drinking the chemical.
Answer:
Question A:17.92 m/s
Question B:0.6 seconds
Explanation:
Question A:
Initial velocity(u)=24m/s
Height(h)=13m
acceleration due to gravity(g)=9.8m/s^2
Final velocity=v
v^2=u^2-2xgxh
v^2=24^2-2x9.8x13
v^2=24x24-2x9.8x13
v^2=576-254.8
v^2=321.2
Take them square root of both sides
v=√(321.2)
v=17.92m/s
Question B:
velocity(v)=17.92m/s
Acceleration due to gravity(g)=9.8m/s^2
Initial velocity(u)=24m/s
Time=t
v=u-gxt
17.92=24-9.8xt
Collect like terms
9.8t=24-17.92
9.8t=6.08
Divide both sides by 9.8
9.8t/9.8=6.08/9.8
t=0.6 approximately
Answer:
<em>The total surface area of the seven little spheres is 1.91 times the total surface area of the bigger sphere.</em>
Explanation:
<u>Volume of a Sphere</u>
The volume of a sphere of radius r is given by:
The volume of each little sphere is:
When the seven little spheres coalesce, they form a single bigger sphere of volume:
Knowing the volume, we can find the radius rb by solving the formula for r:
Multiplying by 3:
Dividing by 4π:
Taking the cubic root:
Substituting:
The surface area of the seven little spheres is:
The surface area of the bigger sphere is:
The ratio between them is:
The total surface area of the seven little spheres is 1.91 times the total surface area of the bigger sphere.
A. The angle at which the arrow must be released to hit the bull's-eye is 20.7 °
B. The arrow will go over the branch.
<h3>A. How to determine the angle</h3>
- Range (R) = 74 m
- Initial velocity (u) = 33 m/s
- Acceleration due to gravity (g) = 9.8 m/s²
- Angle (θ) = ?
R = u²Sine(2θ) / g
74 = 33² × Sine (2θ) / 9.8
Cross multiply
74 × 9.8 = 33² × Sine (2θ)
725.2 = 1098 × Sine (2θ)
Divide both sides by 1098
Sine (2θ) = 725.2 / 1098
Sine (2θ) = 0.6605
Take the inverse of sine
2θ = Sine⁻¹ 0.6605
2θ = 41.3
Divide both sides by 2
θ = 41.3 / 2
θ = 20.7 °
<h3>B. How to determine if the arrow will go over or under the branch</h3>
To determine if the arrow will go over or under the branch situated mid way, we shall determine the maximum height attained by the arrow. This can be obtained as follow:
- Initial velocity (u) = 33 m/s
- Acceleration due to gravity (g) = 9.8 m/s²
- Angle (θ) = 20.7 °
- Maximum height (H) = ?
H = u²Sine²θ / 2g
H = [33² × (Sine 20.7)²] / (2 ×9.8)
H = 6.94 m
Thus, the maximum height attained by the arrow is 6.94 m which is greater than the height of the branch (i.e 3.50 m).
Therefore, we can conclude that the arrow will go over the branch
Learn more about projectile motion:
brainly.com/question/20326485
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Answer:
Explanation:
mass, m = 50 g
moment of inertia, I = 9 x 106-5 kg m^2
radius, r = 0.7 cm
(a) As it moving downwards
Let T be the tension in the string
T = m (g + a) .... (1)
where, a be the acceleration
τ = I α = T r
α = a / r
So, I x a / r = T x r
a = T r^2 / I
Substitute in equation (1) we get
a = m (g + a) r^2 / I
a = mgr^2 / (I - mr^2)
a = 0.050 x 9.8 x 0.007 x 0.007 / (9 x 10^-5 - 0.050 x 0.007 x 0.007)
a = 2.401 x 10^-5 / (87.55 x 10^-6)
a = 0.274 m/s^2
τ = I x α = I x a / r
τ = 9 x 10^-5 x 0.274 / 0.007
τ = 3.52 x 10^-3 Nm
(b) α = a / r
α = 0.274 / 0.007 = 39.14 rad/s^2