Answer:
The water shoots 15.31 m high above the street level.
Explanation:
The gauge pressure drives the motion of the water to whixhever height it will attain. The expression relating the gauge pressure to the height reached by the water, is
P = ρgh
P = Gauge Pressure = 150 kPa = 150,000 Pa
ρ = density of the fluid (water) = 1000 kg/m³
g = acceleration due to gravity = 9.8 m/s²
h = Height reached by the water = ?
150,000 = 1000 × 9.8 × h
h = (150000) ÷ 9800 = 15.306 = 15.31 m
Hope this Helps!!!
Answer:
69.28 m/s
Explanation:
From the question given above, the following data were obtained:
Power = 400 Watt
Time (t) = 10 minutes
Mass (m) = 100 Kg
Velocity (v) =?
Next, we shall convert 10 mins to seconds (s). This can be obtained as follow:
1 min = 60 s
Therefore,
10 mins = 10 × 60
10 mins = 600 s
Next, we shall determine the energy. This can be obtained as follow:
Power = 400 Watt
Time (t) = 600 s
Energy (E) =?
E = Pt
E = 400 × 600
E = 240000 J
Finally, we shall determine how fast the cart is moving. This can be obtained as illustrated below:
Mass (m) = 100 Kg
Energy (E) = Kinetic energy (KE) = 240000 J
Velocity (v) =?
KE = ½mv²
240000 = ½ × 100 × v²
240000 = 50 × v²
Divide both side by 50
v² = 240000 / 50
v² = 4800
Take the square root of both side
v = √4800
v = 69.28 m/s
Thus, the cart is moving with a speed of 69.28 m/s
Entropy is randomness.
It mostly applies to gas particles because they move around randomly and freely
A converging lens is NOT an essential component of a laser.
Hello
This is a problem of accelerated motion, where the acceleration involved is the gravitational acceleration:

, and where the negative sign means it points downwards, against the direction of the motion.
Therefore, we can use the following formula to solve the problem:

where

is the initial vertical velocity of the athlete,

is the vertical velocity of the athlete at the maximum height (and

at maximum height of an accelerated motion) and S is the distance covered between the initial and final moment (i.e., it is the maximum height). Re-arranging the equation, we get