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3 years ago

Which type of mirror would you use to cook a hot dog and why?

Physics

1 answer:

alexandr1967 [171]3 years ago

8 0

As long as it’s a good mirror then any one of them is fine bc at the end of the day i’m getting a hot dog

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A student draws a distance verses time graph to describe the motion of a model train. What does a

maria [59]

Math 2x+125 you welcome

8 0

3 years ago

What velocity will it take to slingshot a planet with 9.8m/s gravity

Yuri [45]

It depends on how close you get to it. Remember that its gravity decreases as you get farther from it.

3 0

4 years ago

Two charged particles are a distance of 1.62 m from each other. One of the particles has a charge of 7.10 nc, and the other has

k0ka [10]

Answer:

A. F=107.6nN

B. Repulsive

Explanation:

According to coulombs law, the force between two charges is express as

F=(Kq1q2) /r^2

If the charges are of similar charge the force will be repulsive and if they are dislike charges, force will be attractive.

Note the constant K has a value 9*10^9

Hence for a charge q1=7.10nC=7.10*10^-9, q2=4.42*10^-9 and the distance r=1.62m

If we substitute values we have

F=[(9×10^9) ×(7.10×10^-9) ×(4.42×10^-9)] /(1.62^2)

F=(282.4×10^-9)/2.6244

F=107.6×10^-9N

F=107.6nN

B. Since the charges are both positive, the force is repulsive

8 0

3 years ago

What is transformation of force?

BigorU [14]

Answer:

Let us develop the transformation of force from a system S where a particle is moving at a speed v to any system S' which is moving relative to system S at a speed V. ...

Explanation:

hope it works out

7 0

3 years ago

Read 2 more answers

A small block of mass m = 0.032 kg can slide along the frictionless loop-the-loop, with loop radius R = 12 cm. The block is rele

Lunna [17]

Answer:

Part a)

$W = 0.15 J$

Part b)

$W = 0.11 J$

Part c)

$U = 0.19 J$

Part d)

$U = 0.038 J$

Part e)

$U = 0.075 J$

Part f)

It is independent of the speed of the object so all part answers will remain the same

Explanation:

Part a)

As we know that Point P is at height 5R while point Q is at height R

so the work done by gravity from P to Q is given as

$W = mg(5R - R)$

$W = 0.032(9.8)(4)(0.12)$

$W = 0.15 J$

Part b)

When it reaches to the top of the loop then its final height from ground is

h = 2R

so work done from P to Q is given as

$W = mg(5R - 2R)$

$W = 3mgR$

$W = 0.11 J$

Part c)

Potential energy at P point is given as

$U = mgH$

$U = 0.032(9.8)(5)(0.12)$

$U = 0.19 J$

Part d)

Potential energy at Q point is given as

$U = mgH$

$U = 0.032(9.8)(0.12)$

$U = 0.038 J$

Part e)

Potential energy at top point is given as

$U = mgH$

$U = 0.032(9.8)(2)(0.12)$

$U = 0.075 J$

Part f)

Since all the answer from part a) to part e) depends only upon the position of the object.

So here we can say that it is independent of the speed of the object so all part answers will remain the same

8 0

4 years ago