PLEASE HELP WILL GIVE BRAINLIEST!!!!

A bugle can be thought of as an open pipe. If a bugle were straightened out, it would be 2.65 mlong.a.) If the speed of sound is

Nezavi [6.7K]

Answer:

(a). The lowest frequency is 64.7 Hz.

(b). The next two resonant frequencies for the bugle are 129.4 Hz and 194.2 hz.

Explanation:

Given that,

Length = 2.65 m

Speed of sound = 343 m

We need to calculate the wavelength

Using formula of wavelength

$\lambda=2l$

Put the value into the formula

$\lambda=2\times2.65$

$\lambda=5.3\ m$

(a). We need to calculate the lowest frequency

Using formula of frequency

$f_{1}=\dfrac{v}{\lambda_{1}}$

Put the value into the formula

$f_{1}=\dfrac{343}{5.3}$

$f_{1}=64.7\ Hz$

(b). We need to calculate the next two resonant frequencies for the bugle

Using formula of resonant frequency

$f_{2}=\dfrac{v}{\lambda_{2}}$

$f_{2}=\dfrac{v}{l}$

Put the value into the formula

$f_{2}=\dfrac{343}{2.65}$

$f_{2}=129.4\ Hz$

For third frequency,

$f_{3}=\dfrac{v}{\lambda_{3}}$

$f_{3}=\dfrac{3v}{2l}$

Put the value into the formula

$f_{3}=\dfrac{3\times343}{2\times2.65}$

$f_{3}=194.2\ Hz$

Hence, (a). The lowest frequency is 64.7 Hz.

(b). The next two resonant frequencies for the bugle are 129.4 Hz and 194.2 hz.

3 0

2 years ago

You are designing a pendulum clock to have a period of 1.0 s. The acceleration of gravity is 9.81 m/s2 . How long should the pen

tatuchka [14]

Answer:

0.25 m

Explanation:

The period of a pendulum is given by

$T=2 \pi \sqrt{\frac{L}{g}}$

where in this case

T = 1.0 s is the period of the pendulum

g = 9.81 m/s^2 is the acceleration due to gravity

L is the length of the pendulum

Re-arranging the equation and solivng for L, we find the length of the pendulum:

$L=g (\frac{T}{2 \pi})^2=(9.81 m/s^2)(\frac{1.0 s}{2\pi})^2=0.25 m$

5 0

3 years ago

What should be the spring constant k of a spring designed to bring a 1200 kg car to rest from a speed of 85 km/h so that the occ

borishaifa [10]

Answer:

k = 5178.8 N/m

Explanation:

As we know that spring mass system will oscillate at angular frequency given as

$\omega = \sqrt{\frac{k}{m}}$

now we have

$\omega = \sqrt{\frac{k}{1200}}$

now the maximum acceleration of the spring block system is at its maximum compression state which is given as

$a = \omega^2 A$

here A= maximum compression of the spring

so here in order to find maximum compression of the spring we will use energy conservation as we know that initial total kinetic energy of the car will convert into spring potential energy

$\frac{1}{2}mv^2 = \frac{1}{2}kA^2$

here we know that

v = 85 km/h

$v = 85 \times\frac{1000}{3600} = 23.61 m/s$

now we have

$(1200)(23.61^2) = kA^2$

$A^2 = \frac{6.68 \times 10^5}{k}$

now from above equation of acceleration we have

$5.0 g = (\frac{k}{m})\sqrt{\frac{6.68 \times 10^5}{k}}$

$5.0(9.81) = \sqrt{k}(0.68)$

$k = 5178.8 N/m$

6 0

3 years ago

Which statement describes a property of a magnet? A. It attracts ferrous materials. B. It could have only one pole (north or sou

hodyreva [135]

Answer:

It attracts ferrous materials

Explanation:

A magnet attracts ferrous materials A ferrous materials are metallic substances or conductors that can conduct heat and electricity. Example of this ferrous materials includes iron, metal etc. Since magnets only can attracts metallic substance to itself, then we can also conclude that they attract ferrous materials since ferrous materials. possesses properties of a metal.

Magnets possesses both north and south poles.

The same of the bar magnets are known to repel each other while unlike poles attract each other.

7 0

3 years ago

The velocities of light in air and glass are 3.0 x 10^8ms and 2.0×10^8ms respectively. If the angle of refraction is 30°, the si

JulijaS [17]

Answer:

0.75

Explanation:

$refractive \: index \: = \frac{3.0 \times {10}^{2} }{2.0 \times {10}^{2} }$