Answer:
the density of the electrum is 14.30 g/cm³
Explanation:
Given that:
The equilibrium fraction of lattice sites that are vacant in electrum = 
Number of vacant atoms = 
the atomic mass of the electrum = 146.08 g/mol
Avogadro's number = 
The Number of vacant atoms = Fraction of lattice sites × Total number of sites(N)
= × Total number of sites(N)
Total number of sites (N) = 
Total number of sites (N) = 
From the expression of the total number of sites; we can determine the density of the electrum;
where ;
= Avogadro's Number
density of the electrum
= Atomic mass
Thus; the density of the electrum is 14.30 g/cm³
Answer:
mwuah
Explanation:
I got u girl, what r u on?
Answer:
Please see the attached file for the complete answer.
Explanation:
Answer:
Option B Lower than
Explanation:
Gauge pressure is a relative measurement based on atmospheric pressure. Gauge pressure can be positive if it is above atmospheric pressure or it can also be negative it is below. On another hand, absolute pressure is an actual pressure in a space and its value has always to be zero or above. Basically absolute pressure is zero if it is in a perfect vacuum. So the measurement of absolute pressure is gauge pressure + atmospheric pressure. This is the reason in normal condition the gauge pressure = absolute pressure - atmospheric pressure and therefore is lower than absolute pressure
