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kolezko [41]
3 years ago
14

A preheater involves the use of condensing steam at 100o C on the inside of a bank of tubes to heat air that enters at I atm and

25o C. The air moves at 5 m/s in cross flow over the tubes. Each tube is 1 m long and has an outside diameter of 10 mm. The bank consists of 196 tubes in a square, aligned array for which ST = SL = 15 mm. What is the total rate of heat transfer to the air? What is the pressure drop associated with the airflow?
(b) Repeat the analysis of part (a), but assume that the tubes have a staggered arrangement with ST = 15 mm and SL = 10 mm.
Engineering
1 answer:
Anna35 [415]3 years ago
8 0

Answer:

Please see the attached file for the complete answer.

Explanation:

Download pdf
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What classification is an E7018?<br><br> will give brainliest
Hunter-Best [27]

Answer: E7018 is a low-hydrogen iron powder type electrode that produces high quality x-ray welds. It can be used in all positions on AC or DC reverse polarity welding current.

Explanation: Hope this helps

3 0
2 years ago
A lagoon is designed to accommodate an input flow of 0.10 m^3/s of nonconservative pollutant with concentration 30 mg/L and deca
dexar [7]

Answer:

Volume of the lagoon required for the decay process must be larger than 86580 m³ = 8.658 × 10⁷ L

Explanation:

The lagoon can be modelled as a Mixed flow reactor.

From the value of the decay constant (0.2/day), one can deduce that the decay reaction of the pollutant is a first order reaction.

The performance equation of a Mixed flow reactor is given from the material and component balance thus:

(V/F₀) = (C₀ - C)/((C₀)(-r)) (From the Chemical Reaction Engineering textbook, authored by Prof. Octave Levenspiel)

V = volume of the reactor (The lagoon) = ?

C₀ = Initial concentration of the reactant (the pollutant concentration) = 30 mg/L = 0.03 mg/m³

F₀ = Initial flow rate of reactant in mg/s = 0.10 m³/s × C₀ = 0.1 m³/s × 0.03 mg/m³ = 0.003 mg/s

C = concentration of reactant at any time; effluent concentration < 10mg/L, this means the maximum concentration of pollutant allowed in the effluent is 10 mg/L

For the sake of easy calculation, C = the maximum value = 10 mg/L = 0.01 mg/m³

(-r) = kC (Since we know this decay process is a first order reaction)

This makes the performance equation to be:

(kVC₀/F₀) = (C₀ - C)/C

V = F₀(C₀ - C)/(kC₀C)

k = 0.2/day = 0.2/(24 × 3600s) = 2.31 × 10⁻⁶/s

V = 0.003(0.03 - 0.01)/(2.31 × 10⁻⁶ × 0.03 × 0.01)

V = 86580 m³

Since this calculation is made for the maximum concentration of 10mg/L of pollutant in the effluent, the volume obtained is the minimum volume of reactor (lagoon) to ensure a maximum volume of 10 mg/L of pollutant is contained in the effluent.

The lower the concentration required for the pollutant in the effluent, the larger the volume of reactor (lagoon) required for this decay reaction. (Provided all the other parameters stay the same)

Hope this helps!

5 0
3 years ago
A lake with an area of 525 [acre] was monitored during a one-month period. The average inflow was 30 [cfs] for the month and the
Alex73 [517]

Answer:

\Delta S = 1581663.5ft^3

Explanation:

We need to calculate the change in storage through the changes given,

That is,

\Delta S = P+I-O-O_{seepage}-E

Where the loss are representing by,

P= Precipitation\\I= Inflow\\O= Outflow\\O_{Seepage}= Outflow by seepage\\E=Evaporation

So calculating the values we have

\Delta S = P+(I-0)-O_{seepage}-E

\Delta S = 4.25+ (30ft^3/s-27ft^3/s)-1.5in-6in

The values inside the are parenthesis need to be konverted as I note here.

(30days(24hr/1day)(3600s/1hr)(1acre.ft/43560ft^3)(1/525acres)(12in/1ft)

That is,

\Delta S = 0.83in\Delta S= (0.83in*1ft/12in)(525acres)\\\Delta S=36.31 acres.ft\\\Delta S=36.31acres.ft*(43560ft^3/acrees.ft)\\\Delta S = 1581663.5ft^3

3 0
3 years ago
A flat site is being considered for a new school that will have a steel frame and brick façade. The steel columns will have a ma
ehidna [41]

Answer:

See explaination

Explanation:

Please kindly check attachment for the step by step solution of the given problem

5 0
3 years ago
Is god real??? Because theres no proof
kakasveta [241]

Answer:

thats a good question that i have been trying to figure out. idk but people seem to have their own gods

Explanation:

6 0
3 years ago
Read 2 more answers
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