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max2010maxim [7]
3 years ago
6

Match the given traits to their definitions.

Engineering
2 answers:
damaskus [11]3 years ago
8 0

Answer:

where the question

Explanation:

Sergio039 [100]3 years ago
8 0

Answer:

?

Explanation:

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On Beverly's last project, the team identified only a few lessons learned. Which approach to lessons learned
Afina-wow [57]

Option C (making lessons learned a regular part of meetings) is the correct approach.

  • As nothing more than a general rule, typically construction companies only plan lessons that have been learned exercises or initiatives towards the end of a particular endeavor or segment.
  • As almost a result of the team knowing, valuable lessons are intended to increase the comprehensive implementation of quality management practices as well as deadlines.

Aside from this, none of the choices are viable methods to learning lessons or gaining knowledge from the past. As a result, the methodology outlined above is the appropriate one.

Learn more about project teamwork here:

brainly.com/question/14279121

7 0
3 years ago
Create a program, using at least one For Loop, that displays the Sales Amounts in each of 4 regions during a period of three mon
kari74 [83]

Answer:

C++ code explained below

Explanation:

/*C++ program that prompts sales for four regions of three sales and prints

the sales values to console */

#include<iostream>

#include<iomanip>

#include<cstring>

using namespace std;

int main()

{

  //set constant values

  const int SALES=3;

  const int REGIONS=4;

  //create an array of four regions

  string regionNames[]={"Region 1","Region 2","Region 3","Region 4"};

  //create a 2D array to read sales

  int sales[REGIONS][SALES];

  //read sales for four regions

  for(int region=0;region<REGIONS;region++)

  {

      cout<<regionNames[region]<<endl;

      for(int sale=0;sale<SALES;sale++)

      {

          cout<<"Enter sales ";

          cin>>sales[region][sale];

      }

  }

  //print sales

  for(int region=0;region<REGIONS;region++)

  {

      cout<<regionNames[region]<<"-";

      for(int sale=0;sale<SALES;sale++)

      {

          cout<<setw(5)<<sales[region][sale];

      }

      cout<<endl;

  }

  //pause program output on console

  system("pause");

  return 0;

}

5 0
4 years ago
If you are involved in a collision and your vehicle is blocking the flow of traffic, you should
zimovet [89]

Answer:

leave the vehicle where it is until the police arrive

Explanation:

4 0
3 years ago
Air at 1600 K, 30 bar enters a turbine operating at steady state and expands adiabatically to the exit, where the pressure is 2.
djyliett [7]

Solution :

The isentropic efficiency of the turbine is given as :

$\eta = \frac{\text{actual work done}}{\text{isentropic work done}}$

  $=\frac{m(h_1-h_2)}{m(h_1-h_{2s})}$

  $=\frac{h_1-h_2}{h_1-h_{2s}}$

The entropy relation for the isentropic process is given by :

$0=s^\circ_2-s^\circ_1-R \ln \left(\frac{P_2}{P_1}\right)$

$\ln \left(\frac{P_2}{P_1}\right)=\frac{s^\circ_2-s^\circ_1}{R}$

$ \frac{P_2}{P_1}=exp\left(\frac{s^\circ_2-s^\circ_1}{R}\right)$

$\left(\frac{P_2}{P_1}\right)_{s=constant}=\frac{P_{r2}}{P_{r1}}$

Now obtaining the properties from the ideal gas properties of air table :

At $T_1 = 1600 \  K,$

$P_{r1}=791.2$

$h_1=1757.57 \ kJ/kg$

Calculating the relative pressure at state 2s :

$\frac{P_{r2}}{P_{r1}}=\frac{P_2}{P_1}$

$\frac{P_{r2}}{791.2}=\frac{2.4}{30}$

$P_{r2}=63.296$

Obtaining the properties from Ideal gas properties of air table :

At $P_{r2}=63.296$,  $T_{2s}\approx 860 \ K$

Considering the isentropic relation to calculate the actual temperature at the turbine exit, we get:

  $\eta=\frac{h_1-h_2}{h_1-h_{2s}}$

$\eta=\frac{c_p(T_1-T_2)}{c_p(T_1-T_{2s})}$

$\eta=\frac{T_1-T_2}{T_1-T_{2s}}$

$0.9=\frac{1600-T_2}{1600-860}$

$T_2= 938 \ K$

So, at $T_2= 938 \ K$, $h_2=975.66 \ kJ/kg$

Now calculating the work developed per kg of air is :

$w=h_1-h_2$

  = 1757.57 - 975.66

  = 781 kJ/kg

Therefore, the temperature at the exit is 938 K and work developed is 781 kJ/kg.

4 0
3 years ago
why is that most solidification does not begin until the temperature falls somewhat below the equilibrium melting temperature? p
Aleksandr [31]

Answer:

Otherwise dies may fail under high operating pressure and temperature. ... The better description and understanding of the phase change processes can be ... occurs only when the temperature is dropped well below the equilibrium temperatures. ... The solidification starts at the bottom and the solidified volume grows more

Explanation:

6 0
3 years ago
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