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katen-ka-za [31]
3 years ago
13

Please answer quickly!!!

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
3 0

Answer:

c=20

Step-by-step explanation:

The diagonals of a rectangle always bisect each other. Therefore, we can set QT=ST:

c=4c-60,\\-3c=-60,\\c=\fbox{20}

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Write a description of how a diagram can help you solve 2x40
stiv31 [10]
Read and understand given problem situations.
Develop and use the strategy: Draw a diagram.
Plan and complete alternative approaches to solving problems.
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4 0
3 years ago
Please help me with this question
Olegator [25]

Answer:

x = 11

Step-by-step explanation:

Since we are given triangle PQR is similar to triangle PTU, we can write a proportion to connect the side lengths:

PQ / PT = QR / TU = PR / PU

We don't really care about QR and TU because the are irrelevant to the problem, so we can remove them:

PQ / PT = PR / PU

Now, we can substitute the values given by the diagram:

70 / 30 = 49 / (x + 10)

We can cross multiply,

70(x + 10) = 30 * 49

And divide by 70 on both sides(too lazy to multiply :P)

x + 10 = 3 * 7

x + 10 = 21

x = 11

5 0
3 years ago
HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
Mkey [24]

Answer:

x=3.6

Step-by-step explanation:

multiply 4 by 9 and then divide by 10

5 0
3 years ago
Read 2 more answers
Answer please i need help
Hunter-Best [27]
32^2 feet so ya know
6 0
3 years ago
Read 2 more answers
Suppose that you take 120 mg of an antibiotic every 4 hr. The​ half-life of the drug is 4 hr​ (the time it takes for half of the
vodomira [7]

Answer:

The steady state amount of antibiotic in the bloodstream when t --> ∞ is 240 mg.

Step-by-step explanation:

Let the amount of antibiotic in one's bloodstream be given as Aₙ (where n = the number of half lives since the start of usage)

Let's follow the time line of events.

At t = 0 hr, the drug is taken

A₀ = 120 mg

At t = 4 hrs, n = 1, the drug is taken again

A₁ = (0.5×A₀) + 120

A₁ = (0.5×120) + 120 = 180 mg

At t = 8 hrs, n = 2, the drug is taken again,

A₂ = (0.5×A₁) + 120

A₂ = (0.5×180) + 120 = 210 mg

At t = 12 hrs, n = 3, the drug is taken again

A₃ = (0.5×A₂) + 120

A₃ = (0.5×210) + 120 = 225 mg

At this point, it becomes evident that at t = 4n hrs, n = n i.e. n half lives later, the general formula for the amount of the antibiotic in the bloodstream is

Aₙ = 0.5Aₙ₋₁ + 120

where Aₙ₋₁ = The amount of antibiotic in the bloodstream at the time t = 4(n-1) and (n-1) half lives later.

For infinite series, that are increasing in this order, as the value of n --> ∞,

Aₙ = Aₙ₋₁ = K

And our general formula becomes

K = 0.5K + 120

0.5K = 120

K = (120/0.5)

K = 240 mg

Hence, the steady state amount of antibiotic in the bloodstream when t --> ∞ is 240 mg.

Hope this Helps!!!

5 0
3 years ago
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