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Jet001 [13]
3 years ago
10

Which energy transformation occurs in the core of a nuclear reactor?

Physics
1 answer:
romanna [79]3 years ago
5 0
The correct answer among the choices given is option B. The energy transformation that occurs in the core of a nuclear reactor is from nuclear energy to thermal energy. In a power plant nuclear fission which involves nuclear energy to heat up water around it. This part is  the core of the process.
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14. If the spring constant of a simple harmonic oscillator is doubled, by what factor will the mass of the system need to change
klio [65]

Lets se

And

\\ \rm\Rrightarrow T=2\pi\sqrt{\dfrac{m}{k}}

\\ \rm\Rrightarrow \sqrt{k}T=2\pi\sqrt{m}

So

\\ \rm\Rrightarrow k\propto m

If spring constant is doubled mass must be doubled

8 0
2 years ago
The decibel level of an orchestra is 90 db, and the violin section achieves a level of 80 dB. How does the sound intensity from
skad [1K]

Answer:

The difference in the decibel corresponses to a constant difference in the loudness perceived.

The refore the sound intensity from the orchestra is like 100 times that of the violin.

Explanation:

4 0
3 years ago
Which is an example of someone responding from a personal perspective?
Anika [276]

Answer:

C

Explanation:

If Ami is saying she likes it then it it personal. If you are speaking from statistics and studies it is impersonal and technically not from there perspective. All of these do this except C.

5 0
3 years ago
Read 2 more answers
Why does water’s high specific heat make it a good coolant for car radiators?.
Alexeev081 [22]

Answer:

Car radiators: Water is used as coolant car radiators. Due to its high specific heat capacity, it can absorb a large amount of heat energy from the engine of the car, but its temperature does not rise too high.

Explanation:

i hope this answer your question if it s wrong please let know

7 0
2 years ago
Read 2 more answers
1. A pair of oppositely charged parallel plates is separated by 5.51 mm. A potential difference of 614 V exists between the plat
Fittoniya [83]

Answer:

Part a)

E = 1.11 \times 10^5 N/C

Part 2)

F = 1.78 \times 10^{-14} N

Part 3)

W = 5 \times 10^{-17} J

Explanation:

Part 1)

As we know that electric field and potential difference related to each other as

E = \frac{\Delta V}{x}

so we will have

\Delta V = 614 V

x = 5.51 mm

so we have

E = \frac{614}{5.51 \times 10^{-3}}

E = 1.11 \times 10^5 N/C

Part 2)

Charge of an electron

e = 1.6 \times 10^{-19} C

now force is given as

F = qE

F = (1.6 \times 10^{-19})(1.11 \times 10^5)

F = 1.78 \times 10^{-14} N

Part 3)

Work done to move the electron

W = F.d

W = (1.78 \times 10^{-14})(5.51 - 2.7) \times 10^{-3}

W = 5 \times 10^{-17} J

5 0
3 years ago
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