Using energy.
Please vote my answer! Branliest!
Do you mean mitosis? If so metaphase.
The battery has both a positive side and a negative side. The potential difference will be the potential of the positive end of the battery minus the potential of the negative end, which will result in positive potential, or power. This potential is what gives the electrons the ability to flow from the positive end to the negative end, or to make a current. While the outside of the insulated wire is the insulator, the inside of the wire has copper, which is the conductor of the current. So, this current will go through the copper of the wire (and not the insulator) from the positive side to the negative.
You said that the useful output power from the model is 6 watts. You also said that the model is 80% efficient. We have no reason to doubt your word, so we know that
(useful output) / (input power) = 80% or 0.8
(6 watts) / (input power) = 0.8
Multiply each side by (input power): 6 watts = (0.8) (input power)
Divide each side by 0.8 : Input power = (6 watts/ 0.8)
<em>Input power = 7.5 watts</em>
Answer:

Explanation:
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