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forsale [732]
3 years ago
12

Which of the following examples could be represented by this free body diagram? (Check all that apply)

Physics
1 answer:
Sedaia [141]3 years ago
7 0

mmmmm ok chill out

its just comment dude


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Which state of matter takes both the shape and volume of its container?
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Use each of the following terms in a separate sentence: tissue<br> organ,and function
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describe an experiment to show how the frequency of a note emitted by a vibrating string depends on the tension of the string
mart [117]
Easy ! 

Take any musical instrument with strings ... a violin, a guitar, etc.

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Pluck any string.  Then, slightly twist the tuning peg for that string,
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Twisting the peg only changed the string's tension; the length
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-- If you twisted the peg in the direction that made the string slightly
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-- If you twisted the peg in the direction that made the string slightly
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3 0
3 years ago
In a game of pool, the cue ball moves at a speed of 2 m/s toward the eight ball. When the cue ball hits the eight ball, the cue
agasfer [191]

Answer:

a)  p₀ = 1.2 kg m / s,  b) p_f = 1.2 kg m / s,  c)   θ = 12.36, d)  v_{2f} = 1.278 m/s

Explanation:

a system formed by the two balls, which are isolated and the forces during the collision are internal, therefore the moment is conserved

a) the initial impulse is

        p₀ = m v₁₀ + 0

        p₀ = 0.6 2

        p₀ = 1.2 kg m / s

b) as the system is isolated, the moment is conserved so

       p_f = 1.2 kg m / s

we define a reference system where the x-axis coincides with the initial movement of the cue ball

we write the final moment for each axis

X axis

        p₀ₓ = 1.2 kg m / s

        p_{fx} = m v1f cos 20 + m v2f cos θ

        p₀ = p_f

       1.2 = 0.6 (-0.8) cos 20+ 0.6 v_{2f} cos θ

        1.2482 = v_{2f} cos θ

Y axis  

       p_{oy} = 0

       p_{fy} = m v_{1f} sin 20 + m v_{2f} cos θ

       0 = 0.6 (-0.8) sin 20 + 0.6 v_{2f} sin θ

       0.2736 = v_{2f} sin θ

we write our system of equations

        0.2736 = v_{2f} sin θ

        1.2482 = v_{2f} cos θ

divide to solve

        0.219 = tan θ

         θ = tan⁻¹ 0.21919

         θ = 12.36

let's look for speed

           0.2736 = v_{2f} sin θ

            v_{2f} = 0.2736 / sin 12.36

           v_{2f} = 1.278 m / s

7 0
3 years ago
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