Answer:
a. autotriploid of species A: 63 chromosomes
b. autotetraploid of species B: 96 chromosomes
c. allotriploid from species A and B: 1) 66 chromosomes and 2) 69 chromosomes
Explanation:
<u>For a.</u>
this species will have 3 haploid sets of chromosomes ('tri' means 3)
one haploid set = 21
21 × 3 = 63 chromosomes
<u>For b.</u>
this species will have 4 haploid sets of chromosomes ('tetra' means 4)
one haploid set = 24
24 × 4 = 96 chromosomes
<u>For c.</u>
there are two ways to do this:
1) two sets of chromosomes from species A and one from species B
42 + 24 = 66 chromosomes
2) one set of chromosomes from species A and two from species B
21 + 48 = 69 chromosomes
Hope that answers the question, have a great day!
I think it would be D hope this helps
Law of segregation states that <span>gametes carry one allele for each trait
As it states that
</span>that during the production of gametes the two copies of each hereditary factor segregate<span> during the production of gametes</span> so that offspring acquire one of the two allele from each parent
so option C is correct
hope it helps
Answer:
If the light was artificial, the plant could survive if it has water. You could use a lamp
Explanation:
A courtship dance or mating ritual hope this helped
