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Katen [24]
2 years ago
12

Pleasee help me pwease

Physics
2 answers:
trasher [3.6K]2 years ago
7 0

Answer:

faults, tell me if im wrong.

Sedbober [7]2 years ago
6 0
I think the answer is (C.) but im not sure
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. A vertical electric field is set up in space to compensate for the gravitational force on a point charge. What is the required
Delicious77 [7]

(a) The required magnitude of the electric field when the point charge is an electron is 5.57 x 10⁻¹¹ N/C.

(b) The required magnitude of the electric field when the point charge is an proton is 1.02 x 10⁻⁷ N/C.

<h3>Magnitude of electric field </h3>

The magnitude of electric field is given by the following equation.

F = qE

But F = mg

mg = qE

E = mg/q

where;

  • E is the electric field
  • m is mass of the particle
  • g is acceleration due to gravity
  • q is charge of the particle
<h3>For an electron</h3>

E = (9.11 x 10⁻³¹ x 9.8)/(1.602 x 10⁻¹⁹)

E = 5.57 x 10⁻¹¹ N/C

<h3>For proton</h3>

E = (1.67 x 10⁻²⁷ x 9.8)/(1.602 x 10⁻¹⁹)

E = 1.02 x 10⁻⁷ N/C

Thus, the required vertical electric field is greater when the charge is proton.

Learn more about electric field here: brainly.com/question/14372859

#SPJ1

4 0
2 years ago
What are the unit for acceleration
Flura [38]
<h3>Answer</h3>

m/s^2 (meter per sec square)

Explanation:

acc = change in velocity/time

= distance/time

----------------

time

= m/s

------

s

=m/s^2

7 0
3 years ago
At the equator, the radius of the Earth is approximately 6370 km. A plane flies at a very low altitude at a constant speed of v
Anna007 [38]

To solve this problem we will apply the concepts related to the kinematic equations of linear motion. For this purpose we will define the speed as the distance traveled in a given period of time. Here the distance is equivalent to the orbit traveled around the earth, that is, a circle. Approaching the height of the aircraft with the radius of the earth, we will have the following data,

R= 6370*10^3 m

v = 219m/s

a = 17m/s^2

The circumference of the earth would be

\phi = 2\pi R

Velocity is defined as,

v = \frac{x}{t}

t = \frac{x}{v}

Herex = \phi, then

t = \frac{\phi}{v} = \frac{2\pi (6370*10^3)}{219}

t = 1.82*10^5s

Therefore will take 1.82*10^5 s or 506 hours, 19 minutes, 17 seconds

3 0
3 years ago
Find the speed of a satellite in a circular orbit around the Earth with a radius 3.57 times the mean radius of the Earth. (Radiu
Gnesinka [82]

The orbiting velocity of the satellite is 4.2km/s.

To find the answer, we need to know about the orbital velocity of a satellite.

<h3>What's the expression of orbital velocity of a satellite?</h3>
  • Mathematically, orbital velocity= √(GM/r)
  • r = radius of the orbital, M = mass of earth
<h3>What's the orbital velocity of a satellite orbiting earth with a radius 3.57 times the earth radius?</h3>
  • M= 5.98×10²⁴ kg, r= 3.57× 6.37×10³ km = 22.7×10⁶m
  • Orbital velocity= √(6.67×10^(-11)×5.98×10²⁴/22.7×10⁶)

=4.2km/s

Thus, we can conclude that the orbiting velocity of the satellite is 4.2km/s.

Learn more about the orbital velocity here:

brainly.com/question/22247460

#SPJ1

8 0
2 years ago
A 500 N force is applied to an object accelerating at 25 m/s^2.<br> what is the mass of the object?
krok68 [10]

Answer:

there are go fella hope u understood

4 0
2 years ago
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