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Katen [24]
3 years ago
12

Pleasee help me pwease

Physics
2 answers:
trasher [3.6K]3 years ago
7 0

Answer:

faults, tell me if im wrong.

Sedbober [7]3 years ago
6 0
I think the answer is (C.) but im not sure
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What are the approximate dimensions of the smallest object on Earth that astronauts can resolve by eye when they are orbiting 27
gayaneshka [121]

Answer:

   s_400 = 16.5 m , s_700 = 29.4 m

Explanation:

The limit of the human eye's solution is determined by the diffraction limit that is given by the expression

                   θ = 1.22 λ / D

where you lick the wavelength and D the mediator of the circular aperture.

In our case, the dilated pupil has a diameter of approximately 8 mm = 8 10-3 m and the eye responds to a wavelength between 400 nm and 700 nm.

by introducing these values ​​into the formula

                 

λ = 400 nm      θ = 1.22 400 10⁻⁹ / 8 10⁻³ = 6 10⁻⁵ rad

λ = 700 nm     θ = 1.22 700 10⁻⁹ / 8 10⁻³-3 = 1.07 10⁻⁴ rad

Now we can use the definition radians

          θ= s / R

where s is the supported arc and R is the radius. Let's find the sarcos for each case

λ = 400 nm       s_400 = θ R

                         S_400 = 6 10⁻⁵ 275 10³

                         s_400 = 16.5 m

λ = 700 nm s_ 700 = 1.07 10⁻⁴ 275 10³

                          s_700 = 29.4 m

8 0
4 years ago
Concept Development
Ostrovityanka [42]

Answer:

The answer is below

Explanation:

The main difference between a liquid and a gas is that when a liquid is under pressure, its volume "won't change apparently. The reason is that the distance between the molecules of a liquid is relatively small, and the molecules of a liquid extensively withstand the compressive forces. This is similar to the distance between the molecules of a solid."

3 0
3 years ago
.Roshan applied a force of 144 N to the side of a cube-shaped wooden block to slide it away from himself . Assuming that he appl
ExtremeBDS [4]
  • side of cube=4cm

Area=side^2=4^2=16cm^2=0.0016m^2

  • Force=144N

\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}

\\ \sf\longmapsto Pressure=\dfrac{144}{0.0016}

\\ \sf\longmapsto Pressure=90000Pa

3 0
3 years ago
The sound intensity from a jack hammer breaking concrete is 2.0W/m2 at a distance of 2.0 m from the point of impact. This is suf
kupik [55]

Answer:

(a) I_{1}=3.2*10^{-3}W/m^{2}

(b) \beta =95dB

Explanation:

Given data

Distance r₁=50 m

Distance r₂=2 m

Intensity I₂=2.0 W/m²

To find

(a) The Sound Intensity I₁

(b) The Sound Intensity level β

Solution

For (a) the Sound Intensity I₁

\frac{I_{1} }{I_{2}}=\frac{(r_{2})^{2}  }{(r_{1})^{2} }\\I_{1} =I_{2}(\frac{(r_{2})^{2}  }{(r_{1})^{2} })\\I_{1}=(2.0W/m^{2} )(\frac{(2m)^{2}  }{(50m)^{2} })\\I_{1}=3.2*10^{-3}W/m^{2}

For (b) the Sound Intensity level β

The Sound Intensity level β is calculated as follow

\beta =(10dB)log_{10}(\frac{I}{I_{o} } )\\\beta  =(10dB)log_{10}(\frac{3.2*10^{-3}W/m^{2}  }{1.0*10^{-12} W/m^{2} } )\\\beta =95dB

8 0
3 years ago
A comet fragment of mass 1.96 × 1013 kg is moving at 6.50 × 104 m/s when it crashes into Callisto, a moon of Jupiter. The mass o
Andrej [43]

Answer:

Recoil speed, 1.17\times 10^{-5}\ m/s                          

Explanation:

Given that,

Mass of the comet fragment, m_1=1.96\times 10^{13}\ kg

Speed of the comet fragment, v_1=6.5\times 10^4\ m/s

Mass of Callisto, m_2=1.08\times 10^{23}\ kg

The collision is completely inelastic. Assuming for this calculation that Callisto's initial momentum is zero. So,

m_1v_1=(m_2+m_2)V

V is recoil speed of Callisto immediately after the collision.

V=\dfrac{m_1v_1}{(m_2+m_2)}\\\\V=\dfrac{1.96\times 10^{13}\times 6.5\times 10^4}{(1.96\times 10^{13}+1.08\times 10^{23})}\\\\V=1.17\times 10^{-5}\ m/s

So, the recoil speed of Callisto immediately after the collision is 1.17\times 10^{-5}\ m/s

6 0
3 years ago
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