2 years ago

Pleasee help me pwease

Physics

2 answers:

trasher [3.6K]2 years ago

7 0

Answer:

faults, tell me if im wrong.

Sedbober [7]2 years ago

6 0

I think the answer is (C.) but im not sure

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a thunderclap sends a sound wave through the air and the ocean below The thunderclap sound wave has a constant frequency of 50 H

Montano1993 [528]

Answer:

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Explanation:

amonbgus

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3 years ago

Recall that if a line is parallel to the vector v and passes through the point P0, which is the tip of the position vector r0, t

Elenna [48]

Answer:

The vector equation of the line is

$\overrightarrow{r}=+t$

Parametric equations for given line are

$x=7+t\\y=-8+6t\\z=3-13t$

Explanation:

The vector equation of the line is given by

$r(t) = r_{o} + tv$

r₀ = (7, -8, 3)

v = (1, 6, -13)

At these points the vector equation for this line is:

$\overrightarrow{r}=\overrightarrow{r_{o}}+t\overrightarrow{v}\\\overrightarrow{r}=+t$

Parametric equations for given line are

$x=7+t\\y=-8+6t\\z=3-13t$

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3 years ago

A spaceship travels at approximately 0. 25c with respect to earth. this means 24 hours at the spaceship will be x hours to us on

Blababa [14]

The time passed on earth is mathematically given as

t' = 24.79 hrs

<h3>What is the time passed on earth?</h3>

Generally, the equation for is time mathematically given as

$t' = \gamma t$

Where

$\gamma = Lorentz\ factor \\\\\gamma = 1/ \sqrt {(1 - v^2/c^2)}$

$t' = t/ \sqrt {(1 - v^2/c^2)}$

Therefore

$t' = 24/ \sqrt {(1 - (0.25c/c)^2) }$

$t'= 24/ \sqrt {(1 - 0.25^2)$

t' = 24.79 hrs

In conclusion, the time passed on earth

t' = 24.79 hrs