Answer y = 1/4 (x+3)^2 + 4
Step-by-step explanation:
If the focus is (-3, 3) and the directrix is y=5, the vertex is at (-3, 4). a = 1/4p, p=1, a=1/4. (h,k) is the vertex.
y=a(x-h)^2 +k
y=1/4(x+3)^2+4
Isn't it (-3,3) that's what I think because it's 1 2 3 but I don't know
Answer:
first of all, the graphs are so poorly plotted,even kn computer...
anyways,
since the blue one ending at x=5 on the x axis,
while actual log ends at x=0 this means
X=x-5
and since, log1=0 but it's 5 in blue graph,
the graph is moved up by 5
hence,
y=5+log(x-5)
F(x) = 3x² - 1
f(-2) = 3(-2)² - 1
f(-2) = 3(4) - 1
f(-2) = 12 - 1
f(-2) = 11
f(x) = x < 1
f(-2) = -2 < 1
f(x) = x + 2
f(-2) = -2 + 2
f(-2) = 0
f(x) = x > 1
f(-2) = -2 > 1
f(-2) = -2 < 1
