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3 years ago

The size of an anion

Chemistry

1 answer:

ozzi3 years ago

6 0

Answer:

Anions have more electrons pulling against the nucleus (the nucleus is losing the tug-of-war), thus making the relative size of the ion larger than the parent atom.

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1.00 g of a compound is combusted in oxygen and found to give 3.14g of CO2 and 1.29 g of H2O. From these data we can tell thatA.

lora16 [44]

Answer:

the compound contains C, H, and some other element of unknownidentity, so we can’t calculate the empirical formula

Explanation:

Mass of CO2 obtained = 3.14 g

Hence number of moles of CO2 = 3.14g/44.0 g = 0.0714 mol

The mass of the carbon in the sample = 0.0714 mol × 12.0g/mol = 0.857 g

Mass of H2O obtained = 1.29 g

Hence number of moles of H2O = 1.29g/18.0 g = 0.0717 mol

The mass of the carbon in the sample = 0.0717 mol × 1g/mol = 0.0717 g

% by mass of carbon = 0.857/1 ×100 = 85.7 %

% by mass of hydrogen = 0.0717/1 × 100 = 7.17%

Mass of carbon and hydrogen = 85.7 + 7.17 = 92.87 %

Hence, there must be an unidentified element that accounts for (100 - 92.87) = 7.13% of the compound.

5 0

3 years ago

2. The model on the right looks bumpy, but when you break a large salt crystal in two, the edges of the split often look straigh

madreJ [45]

Explanation:

because bobo hurts

3 0

4 years ago

Read 2 more answers

In a certain city, electricity costs $ 0.18 per kW ⋅ h . What is the annual cost for electricity to power a lamppost for 5.00 h

LuckyWell [14K]

Answer:

The cost of electricity for 100 W power bulb = $ 32.85

Cost of electricity for 0.025 W fluorescent bulb = $ 8.2125

Explanation:

Cost of electricity = $ 0.18 per KW-H

Time = 5 hour per day

Bulb power = 100 W = 0.1 KW

Fluorescent bulb power = 25 W = 0.025 KW

(a) Cost of electricity for 100 W power bulb

0.1 × 5 × 365 × 0.18 = $ 32.85

(b) Cost of electricity for 0.025 W fluorescent bulb

0.025 × 5 × 365 × 0.18 = $ 8.2125

Therefore the cost of electricity for 100 W power bulb = $ 32.85

Cost of electricity for 0.025 W fluorescent bulb = $ 8.2125

6 0

4 years ago

Determine how many grams of silver would be produced, if 12.83 x 10^23 atoms of copper react with an excess of silver nitrate. G

likoan [24]

<u>Answer:</u> The amount of silver produced in the given reaction is 459.63 g.

<u>Explanation:</u>

According to mole concept:

1 mole of an atom contains $6.022\times 10^{23}$ number of atoms.

For the given chemical equation:

$Cu+2AgNO_3\rightarrow Cu(NO_3)_2+2Ag$

By Stoichiometry of the reaction:

1 mole of copper produces 2 moles of silver.

This means that, $6.022\times 10^{23}$ number of atoms of copper produces $2\times 6.022\times 10^{23}$ number of atoms of silver.

So, $12.83\times 10^{23}$ number of atoms of copper will produce = $\frac{2\times 6.022\times 10^{23}}\times 12.83\times 10^{23}=25.66\times 10^{23}$ number of atoms of silver.