0.009 = 9.10⁻³
hope this helps!
From the reaction, the volume of the oxygen required is 89.6 L.
<h3>What is stoichiometry?</h3>
The term stoichiometry has to do with the process by which the mass of reactants or products in a reaction is obtained from the balanced reaction equation.
In this case, the balanced reaction is equation is;
CH₄ + 2 O₂ → CO₂ + 2 H₂O
Number of moles of CO2 = 88.0 g/44 g/mol = 2 moles
2 moles of O2 produced 1 mole of CO2
x moles of O2 produces 2 moles of CO2
X = 4 moles
1 mole of oxygen occupies 22.4 L hence 4 moles of oxygen occupies 4 * 22.4 L = 89.6 L
Learn more about stoichiometry:brainly.com/question/1384613
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Answer:
<em>The empirical formula is Ag2O.</em>
<em>The empirical formula is Ag2O.Explanation:</em>
<em>The empirical formula is Ag2O.Explanation:The empirical formula is the simplest whole-number ratio of atoms in a compound.</em>
<em>The empirical formula is Ag2O.Explanation:The empirical formula is the simplest whole-number ratio of atoms in a compound.The ratio of atoms is the same as the ratio of moles. So our job is to calculate the molar ratio of Ag to </em><em>2</em><em>O.</em>
<em>do</em><em> </em><em>the</em><em> </em><em>steps</em><em> </em><em>.</em><em>.</em><em>.</em>
To get this into an integer ratio, we divide both numbers by the smaller value.
From this point on, I like to summarize the calculations in a table.
ElementAgMass/gXMolesXllRatiomllIntegers
mAgXXXm7.96Xm0.07377Xll2.00mmm2
mlOXXXXl0.59mm0.0369Xml1mmmml1
There are 2 mol of Ag for 1 mol of O.