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3 years ago

Help please idk how to do this.

Chemistry

1 answer:

marusya05 [52]3 years ago

3 0

Single and Double Replacement reactions are exactly as they sound - they “replace” one or two components, depending on the type, with something else obtained in the reaction.

1. This is a double replacement reaction - see that the SO4 and the OH groups are trading what they’re paired with? OH starts paired with Aluminum, and ends up paired to the Hydrogen, and the SO4 starts with the Hydrogen, but ends up with the Aluminum. Two things being replaced - a double replacement reaction.

2. This is a single replacement reaction - Iron replaces the Hydrogen through the reaction, leaving the Hydrogen inbound afterwards; one thing being replaced - a single replacement reaction.

3. Like 1, this is a double replacement reaction - Fluorine and Oxygen trade partners. Two things being replaced - a double replacement reaction.

Number 4 isn’t complete, and I’m not sure about the goal of the practice problems, so I hope this helps enough to finish the work!

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The ksp of lead iodide is 7.1 × 10-9. a chemical engineer adds 0.0025 mol of ki to a solution of 0.00004 mol pb(no3)2 in 500 ml

inn [45]

Answer is: n<span>o, because the ion product is less than the Ksp of lead iodide. </span>

Chemical dissociation 1: KI(s) → K⁺(aq) + I⁻(aq).
Chemical dissociation 2: Pb(NO₃)₂(s) → Pb²⁺(aq) + 2NO₃⁻(aq).
Chemical reaction: Pb²⁺(aq) + 2I⁻(aq) → PbI₂(s).
Ksp(PbI₂) = 7.1·10⁻⁹.
V = 500 mL ÷ 1000 mL/L = 0.5 L.
c(KI) = c(I⁻) = 0.0025 mol ÷ 0.5 L.
c(I⁻) = 0.005 M.
c(Pb(NO₃)₂) = c(Pb²⁺) = 0.00004 mol ÷ 0.5 L.
c(Pb²⁺) = 0.00008 M.
Q = c(Pb²⁺) · c(I⁻)².
Q = 8·10⁻⁵ M · (5·10⁻³ M)².
Q = 2·10⁻⁹; <span> the ion product.</span>

8 0

2 years ago

Butanal, an aldehyde, can be made from 1-bromobutane, but it requires two reactions in sequence. What are the two reagents that

hammer [34]

Answer:

See explanation and image attached

Explanation:

My aim is to convert 1-bromobutane to butanal. The first step is to react the 1-bromobutane substrate with water. This reaction occurs by SN2 mechanism to yield 1-butanol. Hence reagent A is water.

1-butanol is now reacted with an oxidizing agent such as acidified K2Cr2O7 (reagent B) to yield butanal. Note that primary alkanols are oxidized to alkanals.

These sequence of reactions are shown in the image attached.

4 0

2 years ago

What is the difference between reactants and products?

vitfil [10]

Answer:

The reactants are the substances that start the chemical reaction. The products are the substances that are produced in the chemical reaction.

Explanation:

5 0

2 years ago

Read 2 more answers

A galvanic cell generates a cell potential of 0.32V when operated under standard conditions according to the reaction above. Whi

Ugo [173]

The complete question is shown in the image attached to this answer.

Answer:

Explanation:

Let us quickly remember that the EMF of a cell under non standard conditions in given by the Nernst equation.

This equation states that;

E = E°cell - 0.592/n log Q

Where

E = EMF under non standard conditions

E°cell= standard EMF of the cell

n = number of electrons transferred

Q = reaction quotient

If the reaction quotient is greater than 1 then cell potential is less than the standard cell potential.

The cell that generates the lowest cell potential is the cell depicted in option C because Q has the greatest positive value(Q<1).

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2 years ago

The shielding of electrons gives rise to an effective nuclear charge, Zeff, which explains why boron is larger than oxygen. Esti

Vesna [10]

Zeff = Z - S

Here, Z is the number of protons in the nucleus, that is, atomic number, and S is the number of nonvalence electrons.

For boron, the electronic configuration is 1s₂ 2s₂ 2p₄

Z = 5, S = 2

Zeff = 5-2 = +3

For O, electronic configuration is 1s₂ 2s₂ 2p₄

Z = 8, S = 2

Zeff = 8-2 = +6

Hence, the correct answer is second option, that is, +3 and +6, the Zeff of boron is smaller in comparison to O, thus, boron exhibits a bigger size than O.

3 0

3 years ago