Question

The solubility of CuBr in water at 25°C is measured to be 0.010gL . Use this information to calculate Ksp for CuBr . Round your answer to 2 significant digits.

Answer 1

Answer:

Ksp = 4.86 *10^-9

Explanation:

Step 1: Data given

The solubility of CuBr in water at 25°C is measured to be 0.010 g/L

Temperature = 25.0 °C

Step 2: The balanced equation

CuBr ⇔ Cu+(aq) + Br-(aq)

Step 3: Convert g/L to mol /L

0.010 g/L / / 143.45 g/mol = 6.97 * 10^-5 mol/L

Step 4: Define Ksp

Ksp = [Cu+][Br-]

There is a 1:1 ratio between CuBr and Cu+  and Br¯. T

This means, when 6.97 *10^-5 mol/L  of CuBr dissolves, it produces 6.97 *10^-5 mole per liter of Cu+ and 6.97 *10^-5 mole per liter of Br¯ in solution.

Step 5: Calculate Ksp

Ksp = [Cu+][Br-]

Ksp = [6.97*10^-5 M][6.97*10^-5 M]

Ksp = 4.86 *10^-9