Hydrogenation of cholesterol
1 answer:
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Answer: The empirical formula for the given compound is
Explanation : Given,
Percentage of H = 18 %
Percentage of N = 82 %
Let the mass of compound be 100 g. So, percentages given are taken as mass.
Mass of H = 18 g
Mass of N = 82 g
To formulate the empirical formula, we need to follow some steps:
Step 1: Converting the given masses into moles.
Moles of Hydrogen =
Moles of Nitrogen =
Step 2: Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 5.8 moles.
For Hydrogen =
For Nitrogen =
Step 3: Taking the mole ratio as their subscripts.
The ratio of H : N = 3 : 1
Hence, the empirical formula for the given compound is
Answer:
M = 1.18 mol/L
Explanation:
Moles is denoted by given mass divided by the molecular mass ,
Hence ,
n = moles ,
w = given mass ,
m = molecular mass .
From the information of the question ,
w = 78.3 g
As we known ,
molecular mass of is 189.36 g/mol
m = 189.36 g/mol
moles can be calculated as -
n = 0.413 mol
MOLARITY -
Molarity of a substance , is the number of moles present in a liter of solution .
M = molarity ( unit = mol / L or M )
V = volume of solution in liter ( unit = L ),
n = moles of solute ( unit = mol ),
From the question ,.
V = 350 mL
Since , 1 mL = 10⁻³ L
V = 0.350 L
n = 0.413 mol
Molarity can be calculated as -
M = 1.18 mol/L