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3 years ago

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A 140-kg box is being lowered at constant velocity. A rope is attached to the top of the box, and Jimmy is slightly supporting t

he box from the bottom. If Jimmy is applying 50 N of force to the box, how much force is the rope applying?

1 answer:

Zinaida [17]3 years ago

4 0

Answer:

the anwser is 90

Explanation:

because 140-50=90

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What are the methods of heat transfer?

m_a_m_a [10]

Answer:

Radiation , Conduction and Convection

Explanation:

Those are the ways heat is transferred

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3 years ago

A 120-V rms voltage at 60.0 Hz is applied across an inductor, a capacitor, and a resistor in series. If the rms value of the cur

klemol [59]

Answer:

The impedance of this circuit is 200 ohm.

Explanation:

Given that,

rms voltage = 120 v

Frequency = 60.0 Hz

rms current = 0.600 A

We need to calculate the impedance

Using formula of impedance

$Z=\dfrac{V_{rms}}{I_{rms}}$

Where, $V_{rms}$ = rms voltage

$I_{rms}$ = rms current

Z= impedance

Put the value into the formula

$Z=\dfrac{120}{0.600}$

$Z=200\ Omega$

Hence, The impedance of this circuit is 200 ohm.

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3 years ago

What traction of the radioisotope<br>remains in the body after one day?

r-ruslan [8.4K]

The fraction of radioisotope left after 1 day is $(\frac{1}{2})^{\frac{1}{\tau}}$ , with the half-life expressed in days

Explanation:

The question is incomplete: however, we can still answer as follows.

The mass of a radioactive sample after a time t is given by the equation:

$m(t)=m_0 (\frac{1}{2})^{\frac{t}{\tau}}$

where:

$m_0$ is the mass of the radioactive sample at t = 0

$\tau$ is the half-life of the sample

This means that the mass of the sample halves after one half-life.

We can rewrite the equation as

$\frac{m(t)}{m_0}=(\frac{1}{2})^{\frac{t}{\tau}}$

And the term on the left represents the fraction of the radioisotope left after a certain time t.

Therefore, after t = 1 days, the fraction of radioisotope left in the body is

$\frac{m(1)}{m_0}=(\frac{1}{2})^{\frac{1}{\tau}}$

where the half-life $\tau$ must be expressed in days in order to match the units.

Learn more about radioactive decay:

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3 years ago

Suppose you wanted to break a meter stick over your knee. The cross-section of a meter stick is rectangular. Will it be easier t

LenaWriter [7]

Answer:

It will be easier to break the meter rule with the long side against my knee.

Explanation:

To break the meter rule involves the principle of bending moment. The long side will require less force to generate the same amount of bending moment that will have to be generated to break the meter rule. The short side on the other hand will require more force to generate this mount of bending moment. This is because the shorter has a very small surface area, which concentrates the force on your knee. The pressure is then dissipated as more pressure to your knee. Th longer side has a lesser surface area so, most of the force is used in breaking the meter rule.

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2 years ago

A loop of wire is placed in a uniform magnetic field. For what orientation of the loop is the magnetic flux a maximum? For what

andreyandreev [35.5K]

Answer:

The flux is calculated as φ=BAcosθ. The flux is thereforemaximum when the magnetic field vector is perpendicular to theplane of the loop. We may also deduce that the flux is zero whenthere is no component of the magnetic field that is perpendicularto the loop.

when angle is zero then flux is maximium because when angle zerocos is maximium

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3 years ago