Answer:
the velocity of the mass is 8.44 m/s
Explanation:
Given;
mass of the object, m = 2 kg
spring constant, k = 180 N/m
extension of the spring, x = 0.89 m
The maximum velocity of the mass is calculated as follows;
By the principle of conservation of energy;
Elastic potential energy = kinetic potential energy
¹/₂kx² = ¹/₂mv²
kx² = mv²
Therefore, the velocity of the mass is 8.44 m/s
Evaporation? im not positive but im almost certain that's the answer
Answer:
The awnser is d
Explanation:
i know cause i took the test
Answer:
a) 
, b) 
Explanation:
a) According the Archimedes' Principle, the buoyancy force is equal to the displaced weight of surrounding liquid. The mass of the coal in the barge is:
b) The submersion height is found by using the equation derived previously:
The final submersion height is:
The toy rocket is launched vertically from ground level, at time t = 0.00 s. The rocket engine provides constant upward acceleration during the burn phase. At the instant of engine burnout, the rocket has risen to 72 m and acquired a velocity of 30 m/s. The rocket continues to rise in unpowered flight, reaches maximum height, and falls back to the ground with negligible air resistance.
The total energy of the rocket, which is a sum of its kinetic energy and potential energy, is constant.
At a height of 72 m with the rocket moving at 30 m/s, the total energy is m*9.8*72 + (1/2)*m*30^2 where m is the mass of the rocket.
At ground level, the total energy is 0*m*9.8 + (1/2)*m*v^2.
Equating the two gives: m*9.8*72 + (1/2)*m*30^2 = 0*m*9.8 + (1/2)*m*v^2
=> 9.8*72 + (1/2)*30^2 = (1/2)*v^2
=> v^2 = 11556/5
=> v = 48.07
<span>The velocity of the rocket when it impacts the ground is 48.07 m/s</span>
