The value of Q will be -8 C.
In the presence of an electric or magnetic field, matter experiences a force due to its electric charge.
A moving electric charge generates a magnetic field, and an electric charge has an accompanying electric field.
The information provided in the issue is;
The separation between and is 2m.
The separation between and is 2m.
An origin charge equals +2 C
The electric fields are identical in magnitude but are facing in different directions. As a result, the following relationship can be used
Q/16=1/2
The value of Q will be -8 C.
Learn more about electric charge here
brainly.com/question/8163163
#4174
Answer:
![E=4.61\times 10^{-28}\ J](https://tex.z-dn.net/?f=E%3D4.61%5Ctimes%2010%5E%7B-28%7D%5C%20J)
Explanation:
Given that,
The frequency of local AM radio station, f = 696 KHz = 696000 Hz
We need to find the energy of the frequency at which it is broadcasting.
We know that,
Energy of a wave, E = hf
Where
h is Planck's constant
Put all the values,
![E=6.63\times 10^{-34}\times 696000\\\\=4.61\times 10^{-28}\ J](https://tex.z-dn.net/?f=E%3D6.63%5Ctimes%2010%5E%7B-34%7D%5Ctimes%20696000%5C%5C%5C%5C%3D4.61%5Ctimes%2010%5E%7B-28%7D%5C%20J)
So, the energy of the wave is equal to
.
Answer:
Guysi hate math answer this guy plsss ssss
Ans: Beat Frequency = 1.97HzExplanation:
The fundamental frequency on a vibrating string is
![f = \sqrt{ \frac{T}{4mL} }](https://tex.z-dn.net/?f=f%20%3D%20%20%20%5Csqrt%7B%20%5Cfrac%7BT%7D%7B4mL%7D%20%7D%20)
<span> -- (A)</span>
<span>here, T=Tension in the string=56.7N,
L=Length of the string=0.66m,
m= mass = 8.3x10^-4kg/m * 0.66m = 5.48x10^-4kg </span>
Plug in the values in Equation (A)
<span>so </span>
![f = \sqrt{ \frac{56.7}{4*5.48*10^{-4}*0.66} }](https://tex.z-dn.net/?f=f%20%3D%20%5Csqrt%7B%20%5Cfrac%7B56.7%7D%7B4%2A5.48%2A10%5E%7B-4%7D%2A0.66%7D%20%7D)
<span> = 197.97Hz </span>
<span>the beat frequency is the difference between these two frequencies, therefore:
Beat frequency = 197.97 - 196.0 = 1.97Hz
-i</span>
<em>It's a test on Geography!
</em>