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alisha [4.7K]
3 years ago
12

A Cathode of initial mass 10.00g weigh to 10.05g

Physics
1 answer:
Leto [7]3 years ago
6 0

Answer:

i'm sorry i'm not a physics student

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A cylinder 8 in in diameter and 3 ft long is concentric with a pipe of 8.25 in internal diameter. Between the cylinder and the p
Aleks [24]

Answer:

623.5lb

Explanation:

The answer is detailed in the attached photo

7 0
3 years ago
Sayid made a chart listing data of two colliding objects. A 5-column table titled Collision: Two Objects Stick Together with 2 r
Alborosie

Answer:

6 m/s is the missing final velocity

Explanation:

From the data table we extract that there were two objects (X and Y) that underwent an inelastic collision, moving together after the collision as a new object with mass equal the addition of the two original masses, and a new velocity which is the unknown in the problem).

Object X had a mass of 300 kg, while object Y had a mass of 100 kg.

Object's X initial velocity was positive (let's imagine it on a horizontal axis pointing to the right) of 10 m/s. Object Y had a negative velocity (imagine it as pointing to the left on the horizontal axis) of -6 m/s.

We can solve for the unknown, using conservation of momentum in the collision: Initial total momentum = Final total momentum (where momentum is defined as the product of the mass of the object times its velocity.

In numbers, and calling P_{xi} the initial momentum of object X and P_{yi} the initial momentum of object Y, we can derive the total initial momentum of the system: P_{total}_i=P_{xi}+P_{yi}= 300*10 \frac{kg*m}{s} -100*6\frac{kg*m}{s} =\\=(3000-600 )\frac{kg*m}{s} =2400 \frac{kg*m}{s}

Since in the collision there is conservation of the total momentum, this initial quantity should equal the quantity for the final mometum of the stack together system (that has a total mass of 400 kg):

Final momentum of the system: M * v_f=400kg * v_f

We then set the equality of the momenta (total initial equals final) and proceed to solve the equation for the unknown(final velocity of the system):

2400 \frac{kg*m}{s} =400kg*v_f\\\frac{2400}{400} \frac{m}{s} =v_f\\v_f=6 \frac{m}{s}

7 0
3 years ago
Read 2 more answers
PLEASE HELP QUICK I WILL GIVE BRAINLIEST AnswerTwo descriptions about physical quantities are given below: Quantity A: It is una
zubka84 [21]
Both are quantities of mass
5 0
3 years ago
Read 2 more answers
Can you please help me with this question
yaroslaw [1]

Um it's so dark here I can't find the question lol...

4 0
2 years ago
Mary starts from her house, walks 80 meters south, and stops to chat with her aunt on the sidewalk. After chatting for a few min
Alex

Average speed = (total distance covered) / (time to cover the distance)

Total distance = (80m) + (125m) + (45m) = 250 meters

Overall time = 10 minutes

Average speed = (250 meters) / (10 minutes)

<em>Average speed = 25 meters/minute </em>

Since we're only looking for average speed and not velocity, we don't care about any of the directions, and we don't need to calculate Mary's displacement.

7 0
3 years ago
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