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iogann1982 [59]
3 years ago
15

Why are very high temperatures and pressures required for fusion to occur?

Physics
1 answer:
SashulF [63]3 years ago
7 0

Answer:

b

Explanation:

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A car drives 26.8 m/s south. It
valina [46]

The time for the car to drive directly south is determined as 7.15 s.

<h3>Time for the car to drive directly west</h3>

The time for the car to drive directly south is determined by applying the concept of slope.

slope = Δy/Δx

a = Δv/Δt

Δt = Δv/a

Δt = (26.8)/(3.75)

Δt = 7.15 s

Thus, the time for the car to drive directly south is determined as 7.15 s.

Learn more about acceleration here: brainly.com/question/605631

#SPJ1

7 0
2 years ago
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An unknown material, m1 = 0.49 kg, at a temperature of T1 = 92 degrees C is added to a Dewer (an insulated container) which cont
erastova [34]

Answer:

c_u=1540.5J/kg^{\circ}K

Explanation:

We know that heat relates to mass, specific heat and variation of temperature experimented because of this heat through the equation Q=mc\Delta T=mc(T_f-T_i). The heat released by the unknown material is absorbed by water, so we have Q_u=-Q_w, and we can write:

m_uc_u(T_{uf}-T_{ui})=-m_wc_w(T_{wf}-T_{wi})

Since thermal equilibrium is reached we know that T_{cf}=T_{wf}=T_f=31^{\circ}C=304^{\circ}K, where we have added 273^{\circ} to convert the temperature from Celsius to Kelvin, as <em>we must do</em>. Since we want the specific heat of the unknown material, we do:

c_u=-\frac{m_wc_w(T_f-T_{wi})}{m_u(T_f-T_{ui})}

Which for our values is:

c_u=-\frac{(1.1kg)(4186J/kg^{\circ}K)((304^{\circ}K)-(294^{\circ}K))}{(0.49kg)((304^{\circ}K)-(365^{\circ}K))}=1540.5J/kg^{\circ}K

3 0
3 years ago
A rocket experiences a 45,000 N force as it accelerates at 30 m/s/s. What is the mass of the rocket?
Gre4nikov [31]

Answer:

15,00kg

Explanation:

here's your solution

=> force = 45,000N

=> acceleration = 30m/s^2

=> mass = ?

=> Mass = force/acceleration

=> mass = 45,000/30

=> mass = 15,00kg

hope it helps

6 0
3 years ago
Answer this question​
kow [346]

Answer:

15) C

16) A

17) D

18) D

19) A

22) B

23) D

I might be wrong though

6 0
3 years ago
How can you double the acceleration of an object if you cannot alter the object’s mass?
Lyrx [107]

Answer:

If you double the force, you double the acceleration, but if you double the mass, you cut the acceleration in half.

Explanation:

7 0
2 years ago
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